The fraction names thousandths, so there should
1 answer:
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Answer: b. Only statement (ii) is correct.
Step-by-step explanation:
The given five-number summary of the ages of passengers on a cruise ship is listed below.
Min 1 20 Median 29
38 Max 80
Inter-quartile range =
- According to the 1.5(IQR) criterion for outliers : An data value is an outlier if it lies below
or above
.
Here ,
Since the minimum value> ( ∵ 1 > -7)
It means there is no value below , so there is no low -outlier.
⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.
But the maximum value > (∵ 85 > 65)
It means there are values above .
⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.
Hence, the correct answer is b. Only statement (ii) is correct.
Answer:
Let the vectors be
a = [0, 1, 2] and
b = [1, -2, 3]
( 1 ) The cross product of a and b (a x b) is the vector that is perpendicular (orthogonal) to a and b.
Let the cross product be another vector c.
To find the cross product (c) of a and b, we have
c = i(3 + 4) - j(0 - 2) + k(0 - 1)
c = 7i + 2j - k
c = [7, 2, -1]
( 2 ) Convert the orthogonal vector (c) to a unit vector using the formula:
c / | c |
Where | c | = √ (7)² + (2)² + (-1)² = 3√6
Therefore, the unit vector is
or
[ ,
,
]
The other unit vector which is also orthogonal to a and b is calculated by multiplying the first unit vector by -1. The result is as follows:
[ ,
,
]
In conclusion, the two unit vectors are;
[ ,
,
]
and
[ ,
,
]
<em>Hope this helps!</em>