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Orlov [11]
4 years ago
5

The fraction names thousandths, so there should

Mathematics
1 answer:
iren [92.7K]4 years ago
6 0

Answer:

seven thousand

Step-by-step explanation:

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A square poster has a side length of 26 in. Drawn on the poster are four identical triangles. Each triangle has a base of 8 in.
Firdavs [7]
To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.

Divide the area of the combined areas and the total area to find the probability of landing on a triangle.

A = 1/2bh
      1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)

A = bh
     26 x 26
A = 676 square inches

128/676 = 0.189

There is an approximate probability of 0.19 of hitting a triangle.
6 0
3 years ago
Read 2 more answers
For an acute angle 0, the equation sin(0) = cos(6) is true. What is the value of ? Show or explain your answer
weqwewe [10]

Answer:

\theta =84

Step-by-step explanation:

Given

sin(\theta) = cos(6)

Required

Find \thata\theta

In trigonometry:

If sin(A) = cos(B), then

A + B = 90

So, we have:

\theta + 6 = 90

Collect Like Terms

\theta + 6 -6= 90-6

\theta = 90-6

\theta =84

6 0
3 years ago
50 POINTS!!!43 <br> what is 43 7/8% of $2.35?<br> Round your answer to the nearest cent
Natasha2012 [34]

Answer:

$1.03

Step-by-step explanation:

7/8 = 0.875

then

43 7/8 = 43.875%

43.875/100 = 0.43875

2.35 * 0,43875 = 1.031

Round to the neares cent:

1.03

4 0
3 years ago
Read 2 more answers
Indicate in standard form the equation of the line through the given points.<br> P(0, -4), Q(5.1)
Elan Coil [88]

keeping in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf P(\stackrel{x_1}{0}~,~\stackrel{y_1}{-4})\qquad Q(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{(-4)}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{0}}}\implies \cfrac{1+4}{5}\implies \cfrac{5}{5}\implies 1

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{1}(x-\stackrel{x_1}{0})\implies y+4=x \\\\\\ y=x-4\implies -x+y=-4\implies x-y=4

4 0
3 years ago
Elimination was used to solve a system of equations.
astra-53 [7]

The system of equation that could have led to the equation 9x = 27 is

7x - 2y = 15

x + y = 6

The correct option is the third option

7x - 2y = 15

x + y = 6

<h3>Solving systems of equations</h3>

From the question, we are to determine the system that could have led to 9x = 27


1.

9x + 2y = 21

-9x - 2y = 21

Subtracting, we get

9x + 2y = 21

-9x - 2y = 21

-------------------

18x + 4y = 0

2.

10x - y = 15

x + y = - 12

Subtracting, we get

10x - y = 15

x + y = - 12

---------------------

9x -2y = 27

3.

7x - 2y = 15

x + y = 6

Here, multiply the second equation by 2

2 × [x + y = 6]

2x + 2y = 12

Now, add to the first equation

7x - 2y = 15

2x + 2y = 12

------------------

9x = 27

4.

4x + 3y = 24

-5x - 3y = 3

Subtracting, we get

4x + 3y = 24

-5x - 3y = 3

---------------------

9x + 6y = 21

Hence, the system of equation that could have led to the equation 9x = 27 is

7x - 2y = 15

x + y = 6

The correct option is the third option

7x - 2y = 15

x + y = 6

Learn more on Systems of equations here: brainly.com/question/12691830

#SPJ1

5 0
2 years ago
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