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4 years ago

Could someone tell me if this is correct please

Mathematics

1 answer:

Karo-lina-s [1.5K]4 years ago

5 0

You are correct for 18a through 18c. Nice work.

18a. True (think of it as 21 is less than 27)
18b. False; 0.4 is the same as 0.40
18c. True. Three dollars is much greater than 20 cents
18d. False. 1.9 is the same as 1.90 and can't be smaller than itself
18e. False. The two sides are completely diferrent numbers.
18f. True. The value 6.2 is the same as 6.20
--------------------------------
For problem 19, you have to make the denominators the same. So multiply top and bottom of the first fraction by 10 to go from 4/10 to 40/100

If 40 is in the first box, then 40+40 = 80 is the final numerator. If this is over 100, then 80/100 = 8/10 meaning that 10 goes in the other box.

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A cylinder has a base diameter of 8 inches and a height of 7 inches. What is its volume in cubic inches, to the nearest tenths p

DaniilM [7]

Answer:

351.9 cubic in

Step-by-step explanation:

The volume of a cylinder is hr²π.

r is half the diameter, so 8/2 is 4.

Plug in your h and r and get:

7 * 4² * π

7 * 16 * π

112π

Multiply the π and you'll get about 351.9 cubic in

7 0

3 years ago

HELP WITH 4 QUESTIONS!!!!

m_a_m_a [10]

When dilation is about the origin, as it is here in every case, the image point coordinates are the original (pre-image) coordinates multiplied by the scale factor.

1. Multiply every coordinate value by 5:

... W' = (-5, 10), X' = (-15, -5), Y' = (25, -5), Z' = (15, 10)

2. Multiply every coordinate value by 1/3:

... A' = (-2, 5), B' = (0, 5/3), C' = (1, 10/3)

3. A' = (2, 8), B' = (6, 2), C' = (2, 2)

4. The image coordinates are 5 times the original coordinates, so ...

... the scale factor of the dilation is 5.

5 0

3 years ago

Find the sum 6+9+12+...+93 Sn=

Burka [1]

We notice that:
9-6 = 3
12-9 = 3 , Then we can conclude that this is an arithmetic progression with:
1st term a₁ = 6 and with common difference d = 3

So the first term is 6 and the last term is 93.
the formula of the sum in a A.P is :

S = (a + last term).n/2, n being the rank of the last term. So to be
able to find S, we have to calculate the value of n

We know that the last value of a A.P is :
last value = a₁ + (n-1)d
93 = 6 +(n-1)(3) → 93 = 6 + 3n -3 → n = 90/3 → n = 30 (rank 30th)

Now we can find the sum:
S = (a₁ + last term)n/2

S = (6+93)30/2

S = (99).15 = 1,485

7 0

3 years ago

Write each of the following expressions without using absolute value. |z−6|−|z−5|, if z<5

Andre45 [30]

Answer: 6 - 5

Step-by-step explanation:

|z - 6| - |z - 5| ; z < 5

Since z < 5, then

|z - 6| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 6) = -z + 6

|z - 5| will be the absolute value of a negative number. Replace the absolute value with a negative and parentheses:

-(z - 5) = -z + 5

Now subtract them without the absolute value signs:

-z + 6 - (-z + 5)

Distribute the negative sign:

-z + 6 + z - 5

-z + z = 0 which leaves:

6 - 5

3 0

4 years ago

Read 2 more answers

Sick-leave time used by employees of a firm in a course of one month has approximately normal distribution, with a mean of 200 h

Usimov [2.4K]

Answer:

a)0.62% probability that total sick leave for next month will be less than 150 hours.

b) 225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 200, \sigma = \sqrt{400} = 20$

a.Find the probability that total sick leave for next month will be less than 150 hours.

This probability is the pvalue of Z when X = 150. So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{150 - 200}{20}$

$Z = -2.5$

$Z = -2.5$ has a pvalue of 0.0062.

So there is a 0.62% probability that total sick leave for next month will be less than 150 hours.

b.In planning schedules for next month, how much time should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

This is the value of X when Z has a pvalue of 0.90. So $Z = 1.28$

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{X - 200}{20}$

$X - 200 = 20*1.28$

$X = 225.6$

225.6 hours should be budgeted for sick leave if that amount is to be exceeded with a probability of only 0.10.

6 0

4 years ago