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2 years ago

Find 90% of 0.4No equation needed.

Mathematics

2 answers:

myrzilka [38]2 years ago

8 0

90% = 0.9

0.9 * 0.4

= 0.36

erma4kov [3.2K]2 years ago

3 0

......The answer is 0.36

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Find the surface area of the prism. 5 in. - 3 in. 8 in.

steposvetlana [31]

Answer:

5.10,3.6,8.12 is the surface area of prism

Step-by-step explanation:

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3 years ago

Which expression is the additive inverse of n? A. 1/n B. -n C. -1/n D. -(-n)

Marrrta [24]

The additive inverse of something is whats added to the original to get 0

So in this case n - n = 0, which is B :)

6 0

3 years ago

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A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Please help me as soon as possible

Alex777 [14]

Answer:

I think the choose (B)

5x/x + 3/x

5 0

2 years ago

Read 2 more answers

Diego bought a drone for $35 off the regular price of $720.00. if there is 7% tax and a $6.50 shipping fee, what is the total pr

creativ13 [48]

Answer:

$739.45

Step-by-step explanation:

$720 - $35 = $685

$685 + 7% = $732.95

$732.95 + $6.50 = $739.45

4 0

3 years ago

Find 90% of 0.4No equation needed. ​

Find 90% of 0.4No equation needed.