Answer:
40
Step-by-step explanation:
Answer:
16.7
Step-by-step explanation:
We can use the Pythagorean theorem, a^2 + b^2 = c^2.
a = 11
c = 20
11^2 + b^2 = 20^2
121 + b^2 = 400
b^2 = 279
b = sqrt(279) = 16.7
Answer:
19.2
Step-by-step explanation:
Answer:
82
Step-by-step explanation:
Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.
The sum of 4 consecutive numbers:
1st = x
2nd = x + 1
3rd = x + 2
4th = x + 3
The sum of 4 consecutive number is 326.
1st + 2nd + 3rd + 4th = 326
x + (x + 1) + (x + 2) + (x + 3) = 326
Combine like terms:
4x + 6 = 326
Then we subtract 6 from both sides to isolate 4x:
4x + 6 - 6 = 326 - 6
4x = 320
Then we divide both sides by 4 to isolate x:
4x/4 = 320/4
x = 80
So the first number is 79
Now to get the second, let's just add 1.
80 + 1 = 81
Let's check if our answer would be correct:
80 + 81 + 82 + 83
= 326