Answers:
The formula is [f(-1)-f(-4)]/[3]
The value of f(-1) is 3
The value of f(-4) is -3
The average rate of change is 2
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Explanation:
For the first blank, we use the formula
[ f(b) - f(a) ]/[ b - a ]
where 'a' and 'b' are the endpoints for the x interval
In this case, a = -4 and b = -1. When you plug those values into the formula above, you get...
[ f(b) - f(a) ]/[ b - a]
[ f(-1) - f(-4)]/[ -1 - (-4) ]
[ f(-1) - f(-4)]/[ -1+4 ]
[ f(-1) - f(-4)]/[ 3 ]
which is why the answer is choice C for the first blank
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To compute the value of f(-1), we draw a vertical line through -1 on the x axis. This vertical line crosses the diagonal function graph at the point (-1,3). The y value of this point is what we want. Plugging in x = -1 leads to y = 3. This is why f(-1) = 3
If you want, you can draw a horizontal line through (-1,3) and you'll see it touching 3 on the y axis.
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Follow similar steps as above to compute f(-4). Draw a vertical line through x = -4 on the x axis. Mark the point where the vertical line crosses the diagonal line. This point is (-4,-3). Optionally draw a horizontal line over til you hit the y axis and you'll find that y = -3 corresponds to x = -4
This is why f(-4) = -3
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We'll use the last three sections to compute the average rate of change. Everything combines together building up to this moment.
From the first part, we had the formula
[ f(b) - f(a) ]/[ b - a ]
[ f(-1) - f(-4)]/[ 3 ]
We can replace the "f(-1)" with 3 since we found that f(-1) = 3
Similarly, f(-4) = -3 so we can replace the "f(-4)" with -3
Doing those replacements and simplifying leads to...
[ f(-1) - f(-4)]/[ 3 ]
[ 3 - (-3)]/[ 3 ]
[ 3 + 3]/[ 3 ]
6/3
2
So the average rate of change is 2
Note: because the entire graph is a straight line, the average rate of change for any interval a < x < b is going to be equal to the slope m. In this case, the slope of the line is m = 2/1 = 2. We move up 2 units each time we move to the right 1 unit along the diagonal line.
Answer:
Step-by-step explanation:
x^2 + 1 -2x + 5
x^2 - 2x + 6
All the angles created by the transversal intersecting through a pair of parallel lines have got many names and connections with each other, like Alternate Angles, Corresponding angles, consecutive interior angles etc.
As per the question statement, We are given a pair of parallel lines which is cut by a transversal. We are supposed to mark the following angles.
Alternate Interior Angles, Alternate Exterior Angles, Corresponding Angles and Consecutive Interior Angles.
Here is an attached image of the same with angles marked on it.
Alternate Interior Angles: ∠
= ∠
and ∠
=∠
Alternate Exterior Angles: ∠
=∠
and ∠
=∠
Corresponding Angles: ∠=∠ , ∠=∠ , ∠=∠ and ∠=∠
Consecutive Interior Angles: ∠=∠ and ∠=∠
- Parallel Lines: Parallel lines are those straight lines that are, no matter how far they are extended, always the same distance apart from one another.
- Transversal Line: In geometry, a transversal line intersects two lines in the same plane at two different locations.
To learn more about Transversal Line click on the link given below:
brainly.com/question/24770636
#SPJ1
Answer:
the answer is saltiness, why?
Step-by-step explanation:
because when i was little my bro used to ask me to go up and down with my mouth on his cucumber and i hated it but he offered me candy. Anyway now he gives me 5$ so ill do it more and as many times :D so i can get a new robucks card
Y = 3x....where y is # pgs read and x = # of minutes
0 minutes....x = 0
y = 3(0)
y = 0
ordered pair (0,0)
1 minute...x = 1
y = 3(1)
y = 3
ordered pair (1,3)
2 minutes...x = 2
y = 3(2)
y = 6
ordered pair (2,6)
3 minutes...x = 3
y = 3(3)
y = 9
ordered pair (3,9)
