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likoan [24]
3 years ago
6

Oliver took a math quiz last week. There were 25 problems on the quiz and Oliver answered 80% of them correctly. How many proble

ms did Oliver get correct?
Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

He answered 20 questions correctly.

Step-by-step explanation:

25×.8(80%) = 20.

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The vertex of this parabola is at (5, -4). Which of the following could be its equation? A.y = 2(x + 5)2 + 4
astraxan [27]
I think d or b but if I am wrong sorry
4 0
2 years ago
Read 2 more answers
If the function f(x) = -1/2x - 7 were graphed, which of the following would be true?
Fittoniya [83]
ANSWER

D. As the x-values increase, the y-values would decrease

EXPLANATION

The given function is
y =  -  \frac{1}{2} x - 7


The slope of this function is
m =  -  \frac{1}{2}

Since the slope is negative, there is a negative or an inverse relationship between x and y.

As the values of x increases, the values of y decreases.

Also, as the values of x decreases, the values of y increases.

The first option is not true because as x is becoming bigger and bigger negatively, y will become positive.

For instance, when
x =  - 40
y =  -  \frac{1}{2} ( - 40) - 7


This implies that,

y = 20 - 7 = 13

Options B is obviously not true because the function has a negative relationship between x and y.


Option C is also false because, x can be positive since it is the independent variable.

See graph



Therefore, the correct answer is option D.




5 0
3 years ago
9x+18+3x=1
Katen [24]
The error is in the second step they subtracted 3 from both sides but it was a 3x, which you can not do.
Correction.
9x+18+3x=1
12x+18=1
12x=-17
x=-17/12
3 0
2 years ago
Read 2 more answers
Find the point on the parabola y^2 = 4x that is closest to the point (2, 8).
guapka [62]

Answer:

(4, 4)

Step-by-step explanation:

There are a couple of ways to go at this:

  1. Write an expression for the distance from a point on the parabola to the given point, then differentiate that and set the derivative to zero.
  2. Find the equation of a normal line to the parabola that goes through the given point.

1. The distance formula tells us for some point (x, y) on the parabola, the distance d satisfies ...

... d² = (x -2)² +(y -8)² . . . . . . . the y in this equation is a function of x

Differentiating with respect to x and setting dd/dx=0, we have ...

... 2d(dd/dx) = 0 = 2(x -2) +2(y -8)(dy/dx)

We can factor 2 from this to get

... 0 = x -2 +(y -8)(dy/dx)

Differentiating the parabola's equation, we find ...

... 2y(dy/dx) = 4

... dy/dx = 2/y

Substituting for x (=y²/4) and dy/dx into our derivative equation above, we get

... 0 = y²/4 -2 +(y -8)(2/y) = y²/4 -16/y

... 64 = y³ . . . . . . multiply by 4y, add 64

... 4 = y . . . . . . . . cube root

... y²/4 = 16/4 = x = 4

_____

2. The derivative above tells us the slope at point (x, y) on the parabola is ...

... dy/dx = 2/y

Then the slope of the normal line at that point is ...

... -1/(dy/dx) = -y/2

The normal line through the point (2, 8) will have equation (in point-slope form) ...

... y - 8 = (-y/2)(x -2)

Substituting for x using the equation of the parabola, we get

... y - 8 = (-y/2)(y²/4 -2)

Multiplying by 8 gives ...

... 8y -64 = -y³ +8y

... y³ = 64 . . . . subtract 8y, multiply by -1

... y = 4 . . . . . . cube root

... x = y²/4 = 4

The point on the parabola that is closest to the point (2, 8) is (4, 4).

4 0
2 years ago
A.8.4 t=_______kg
Art [367]
<h2><u>ANS</u></h2>

A) 8400 kg

B) 10 km

C) 0.231 kg

D) 6000000 g

E) 0.007 t

F) 0.00125 kg

G) 3900 kg

H) 2 kg

I) 5000 g

J) 3.6 kg

<h3><u>T</u><u>hank</u> <u>You</u> !!!</h3>

7 0
2 years ago
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