Please helpppppppppppp

Tính đạo hàm của y=2x-1-căn3x-0

adoni [48]

Answer:

The derivative is

$\frac{dy}{dx} = 2 - \frac{2\sqrt3}{\sqrt x}\\$

Step-by-step explanation:

The function is given by

$y = 2x - 1 - \sqrt {3x}$

Differentiate with respect to x, we get

$\frac{dy}{dx} = 2 - 0 - \frac{2\sqrt3}{\sqrt x}\\\\\frac{dy}{dx} = 2 - \frac{2\sqrt3}{\sqrt x}\\$

7 0

2 years ago

Jamar works at Jay's Jeweler. He earns $385 a week plus commission. Last week his sales totaled $1,680. If his commission is 25%

-BARSIC- [3]

$805

25% of $1,680 is $420 .
$420+$385= $805

4 0

1 year ago

Read 2 more answers

You are dealt one card from a satndard 52-card deck. Find the probability of being dealt an ace or a 7

ruslelena [56]

Answer:

2/13 or 15.38%

Step-by-step explanation:

Number of Aces in a deck = 4

Number of 7s in a deck = 4

Number of cards in a deck = 52

Probability of A or 7 = (4 Aces + 4 Sevens) / 52 cards 8 cards / 52 cards

This simplifies to 2/13 or 15.38%

3 0

1 year ago

I took a picture of the question

cluponka [151]

Answer:

27.5 inches^2

Step-by-step explanation:

Area of a triangle =

$\frac{bh}{2}$

Plugging in the equation,

$\frac{11 \times 5}{2} = \frac{55}{2} \\ \frac{55}{2} = 27.5$

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

1 year ago