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3 years ago

5

Please helpppppppppppp

1 answer:

Gekata [30.6K]3 years ago

4 0

D. The measure of TRU is 72

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How to solve it&&&&&&&&&&&

Dimas [21]

Answer:

y = 4 and x = 12

Step-by-step explanation:

Step by step explanation in the pic. Atleast the way I did it.

8 0

3 years ago

Can someone help me with this question? Thank you!

Natali [406]

Answer:

11

Step-by-step explanation:

22 is the largest number you are given in this diagram. 0 is the smallest. that would be your first step.

Next think about it as if you already know your midpoint, as in, midpoint being half of your ending value.

Lastly, you want to divide 22 in half, since midpoint is half of your line segment, and then answer you get is 11

3 0

3 years ago

Please help with one of these

LekaFEV [45]

Number 10 is Answer: y=2.5/2x+3.5

Step-by-step explanation:

The 3.5 is the y intercept because it is when x is 0. The slope is just the change in y over the change in x

3 0

3 years ago

M - 7 < 6 please help me

Citrus2011 [14]

<span>the answer is M<13 for problems like this you can go to https://www.cymath.com/answer.php?q=solve%20M%20-%207%3C%206 to solve your answer</span>

7 0

3 years ago

Please help! i dont understand

kvv77 [185]

QUESTION 1

The given inequality is

$y\leq x-3$ and $y\geq -x-2$ .

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

$-2\leq 3-3$ and $-2\geq -3-2$ .

$-2\leq 0$ :True and $-2\geq -5$ :True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is

$y\:>\:-3x+3$ and $y\:>\: x+2$ .

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

$4\:>\:-3(1)+3$ and $4\:>\: 1+2$ .

$4\:>\:0$ :True and $4\:>\: 3$ :True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is

$y\leq 3x-6$ and $y\:>\: -4x+2$ .

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

$-2\leq 3(0)-6$ and $-2\:>\: -4(0)+2$ .

$-2\leq -6$ :False and $-2\:>\:2$ :False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is

$2x-y\:$ and $x+y\:>\:-1$ .

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

$2(0)-3\:$ and $0+3\:>\:-1$ .

$-3\:$ :True and $3\:>\:-1$ : True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is

$y\:>\:2x-3$ and $y\:$ .

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

$0\:>\:2(-3)-3$ and $0\:$ .

$0\:>\:-9$ ;True and $0\:$ :True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

3 0

3 years ago