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3 years ago

How do i calculate a new average with the old average

1 answer:

7 0

Answer: to calculate the new average after then nth number, you multiply the old average by n−1, add the new number, and divide the total by n. In your example, you have the old average of 2.5 and the third number is 10.
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If it is 7:20 am how many minutes until 7:46 am

exis [7]

26 minutes until 7.46am

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4 years ago

Help please help please help please

user100 [1]

Answer:

Once upon a time, there were a two person family who lived out in the woods. The father took great care of the son. The father was a Botany, but had retired because of his age. But still he loved plants and grew a garden. The garden included Giant Bird of Paradise, Carnations, Irises, and ofc roses. He loved plants so much that he went out to dig a hole and plant different flowers and plants every spring. When the son grew older he helped the father with the garden. Two years later his son was accused of murder, but the body wasn't found. Next spring came and the father went out to dig. He couldn't Finnish it. He called his son and say he couldn't do the garden thing, because of his age. The son said don't dig there that's where he hid the bodies. The police came to dig the holes and try to find the bodies, but none of them were found. The father called the son again, and the son said thats all I can do for you right now.

Step-by-step explanation:

3 0

3 years ago

5x – 2x + 7 – x = ?x + ?

fomenos

Step-by-step explanation:

5x – 2x + 7 – x = ?x + ?

I need the answer for "no solution" and "infinite solutions".

NO SOLUTION:

no solution because any value you give to x is not solvable, it remains +7

5x – 2x + 7 – x = ?x + ?

2x = 2x + 7

INFINITE SOLUTION

infinite solutions because any value you give to x is solvable

5x – 2x + 7 – x = ?x + ?

5x – 2x + 7 – x = 2x + 7

2x + 7 = 2x + 7

8 0

2 years ago

The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

Read 2 more answers

Write an equation of a like that passes through the points (9,5) and (6,7)

hodyreva [135]

Answer:

y=-2/3x+11

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(7-5)/(6-9)

m=2/-3

m=-2/3

y-y1=m(x-x1)

y-5=-2/3(x-9)

y=-2/3x+18/3+5

y=-2/3x+6+5

y=-2/3x+11

5 0

3 years ago