A circle is divided into 6 sectors in such a way that the angles of the sectors are in arithmetic

Suppose you have $1,950 in your savings account at the end of a certain period of time. You invested $1,700 at a 6.88% simple an

Licemer1 [7]

Answer:

He invest for 2 years.

Step-by-step explanation:

Given : Suppose you have $1,950 in your savings account at the end of a certain period of time. You invested $1,700 at a 6.88% simple annual interest rate.

To find : How long, in years, did you invest your money?

Solution :

Applying simple interest formula,

$A=P(1+r)^t$

Where, A is the amount A=$1950

P is the principal P=$1700

r is the interest rate r=6.88%=0.0688

t is the time

Substitute the values in the formula,

$1950=1700(1+0.0688)^t$

$\frac{1950}{1700}=(1.0688)^t$

$1.147=(1.0688)^t$

Taking log both side,

$\log(1.147)=\log ((1.0688)^t)$

Applying logarithmic formula, $\log a^x=x\log a$

$\log(1.147)=t\log (1.0688)$

$t=\frac{\log(1.147)}{\log (1.0688)}$

$t=2.06$

Approximately, He invest for 2 years.

5 0

3 years ago

X cuanto multiplico 15 para q m de 100?

grin007 [14]

Answer:

1500 is your answer

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A gumball machine contains 23 green gumballs, 52 red gumballs, 34 blue gumballs, 61 yellow gumballs, and 30 pink gumballs.

insens350 [35]

23+52+34+61+30=200. Your answer of total gumballs is 200. At least I hope you meant to ask that. :)

8 0

3 years ago

Read 2 more answers

The Dow Jones Industrial Average has had a mean gain of 432 pear year with a standard deviation of 722. A random sample of 40 ye

trasher [3.6K]

Answer:

66.98% probability that the mean gain for the sample was between 250 and 500.

Step-by-step explanation:

To solve this problem, it is important to know the Normal probability distribution and the Central limit theorem.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .