To find the rate in miles per hour, divide the miles by the hours.
(1 1/2 miles)/(3/5 hour) =
= 3/2 miles * (5/3 hour)
= 5/2 mph
= 2 1/2 mph
Her walking rate is 2 1/2 mph.
(4 1/2 miles) / ( 2 1/2 mph) =
= 9/2 miles / (5/2 mph)
= 9/2 * 2/5 hours
= 9/5 hours
= 1 4/5 hours
From 9:00 a.m. to 11 a.m., she has 2 hours, but she only needs 1 4/5 hours to walk, so she will make it to work on time.
Answer: -6
Step-by-step explanation:
-x-1=5
-x=5+1
-x=6
divide both sides by -1
x=-6
Answer:
Letter C
y = plus-or-minus StartRoot StartFraction x + 10 Over 7 EndFraction EndRoot
Step-by-step explanation:
Just took the test.
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
Answer: 
Step-by-step explanation:
Given

from the figure
![\angle HIE=\angle GIF\quad [\text{vertically opposite angles}]\\\angle HID+\angle DIE=\angle GIF\\15^{\circ}+(18x)^{\circ}-2^{\circ}=103^{\circ}\\(18x)^{\circ}=103^{\circ}-13^{\circ}\\\\x=\dfrac{90^{\circ}}{18}\\\\x=5^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20HIE%3D%5Cangle%20GIF%5Cquad%20%5B%5Ctext%7Bvertically%20opposite%20angles%7D%5D%5C%5C%5Cangle%20HID%2B%5Cangle%20DIE%3D%5Cangle%20GIF%5C%5C15%5E%7B%5Ccirc%7D%2B%2818x%29%5E%7B%5Ccirc%7D-2%5E%7B%5Ccirc%7D%3D103%5E%7B%5Ccirc%7D%5C%5C%2818x%29%5E%7B%5Ccirc%7D%3D103%5E%7B%5Ccirc%7D-13%5E%7B%5Ccirc%7D%5C%5C%5C%5Cx%3D%5Cdfrac%7B90%5E%7B%5Ccirc%7D%7D%7B18%7D%5C%5C%5C%5Cx%3D5%5E%7B%5Ccirc%7D)