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Kitty [74]
4 years ago
8

James wants to construct a regular hexagon inscribe in a circle with center O and diameter PQ

Mathematics
1 answer:
Brums [2.3K]4 years ago
6 0

Answer:

B. Place the compass at P and draw an arc of length OP across the circle.

Below is the diagram for help.

Step-by-step explanation:

We are given with an already constructed circle of diameter PQ and OP as radius.

To draw a regular hexagon(six-sided), we need to make first cut on the circle of an arc equal to radius of the circle taking any point of the diameter as center

So here, We will consider P as a center and take an arc of length OP and make a cut on the circle.

This would be the first step and James need to repeat the same steps by considering the newly formed cut as center each time.

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The width of a box is x units.
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Answer:

3x² + 30x

Step-by-step explanation:

width of a box = x units.

height of a box = 3 units.

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= (x + 10) * x * 3

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Volume of the box = 3x² + 30x

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Someone please help and show work!! I will also mark brainliest. I’ll appreciate it.
Eduardwww [97]

Answer:

1. 53

2. 20

3. 37

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Step-by-step explanation:

Since your trying to find the hypotenuse you equation is...

1. 28^2 + 45^2 = C^2

    784 + 2025 = C^2

      Square Root 2809= C^2

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So after you square root 2809 you get 53.

2. 12^2 + 16^2 = C^2

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So after you square root 400 you get 40.

3.  12^2 + 35^2 = C^2

    144 + 1225 = C^2

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So after you square root 1359 you get 37.

4. 20^2 + 21^2 = C^2

   400 + 441 = C^2

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aleksandrvk [35]

Answer:

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