James wants to construct a regular hexagon inscribe in a circle with center O and diameter PQ

Mathematics

1 answer:

Brums [2.3K]3 years ago

6 0

Answer:

B. Place the compass at P and draw an arc of length OP across the circle.

Below is the diagram for help.

Step-by-step explanation:

We are given with an already constructed circle of diameter $PQ$ and $OP$ as radius.

To draw a regular hexagon(six-sided), we need to make first cut on the circle of an arc equal to radius of the circle taking any point of the diameter as center

So here, We will consider $P$ as a center and take an arc of length $OP$ and make a cut on the circle.

This would be the first step and James need to repeat the same steps by considering the newly formed cut as center each time.

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$Given : \frac{(x^\frac{2}{5})^9\;.\;(x^\frac{-4}{15})}{x^\frac{1}{3}}$

$\implies {(x^\frac{18}{5})\;.\; (x^\frac{-4}{15})}\;.\;(x^\frac{-1}{3})$

$\implies x^(^\frac{18}{5} ^-^\frac{4}{15}^-^\frac{1}{3}^)$

$\implies x^(^(^\frac{54 - 4}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{50}{15}^)^-^\frac{1}{3}^) = x^(^(^\frac{10}{3}^)^-^\frac{1}{3}^) = x^(^\frac{9}{3}^) = x^3$