<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
The answer is letter d because the y collum is y=y•2+1
Answer: y = 1/2 or y = -1/2
Step-by-step explanation:
First move the 1 to the side with the 0
-4y^2 = -1 // -1 because when you move a number to the other side of the equation you have to multiply -1
Then divide by -4 on each side
y^2 = 1/4
square root each side
|y| = 1/2 // sq rt y^2 becomes an absolute value because when you square root a square it automatically becomes an absolute value
so the answer would be y = 1/2 or -1/2
to check just put it into the equation as y. Both work.
Step-by-step explanation:
(p-3)[x²+4]+4=0
(p-3)[x²+4]=-4
(p-3)=-4/x²+4
p=-4/x²+4+3
p=-4+3(x²+4)/x²+4
p= -4+3x²+12/x²+4
p=8+3x²/x²+4
The answer is <em>x</em>=5.
Solve for <em>x</em>. (The question mark should be <em>x</em>.)
