Homework help answering math questions

Mathematics

1 answer:

Margarita [4]3 years ago

4 0

Boys in cool places it’s just amazing James Charles

You might be interested in

How do you use the scale on a scale drawing to find the measurements of actual projects

vampirchik [111]

Answer:

multiply the scale drawings side lengths by the scale

Step-by-step explanation:

for instance, if i have a square shaped scale drawing with the side lengths of 4in, and the scale is 2in, i would multiply 4 by 2, and the actual drawing's side lengths would be 6.

if i did not know the scale and i knew the actual drawings side lengths and the scale drawings side lengths, i would divide the corresponding lengths

example: rectangular scale drawing with the lengths, 5, 5, 10, and 10. and an actual drawing with the lengths 10, 10, 20, and 20. if i divide 20 by 10 or 10 by 5, i'd get 2, the scale

5 0

3 years ago

The first terms of an infinite geometric sequence, Un are 2, 6, 18, 54... The first terms of a second infinite geometric sequenc

gladu [14]

Answer:

r = 9 and m = 112

Step-by-step explanation:

$\sum_{k=1}^{225}W_{k}=\sum_{k=0}^{m}4r^{k}$

Write W in terms of U and V.

$\sum_{k=1}^{225}(U_{k}+V_{k})=\sum_{k=0}^{m}4r^{k}\\\sum_{k=1}^{225}U_{k}+\sum_{k=1}^{225}V_{k}=\sum_{k=0}^{m}4r^{k}$

Define U and V using geometric series formula.

$\sum_{k=1}^{225}2(3)^{k-1}+\sum_{k=1}^{225}2(-3)^{k-1}=\sum_{k=0}^{m}4r^{k}$

Use sum of geometric series formula.

$2(\frac{1-(3)^{225}}{1-3})+2(\frac{1-(-3)^{225}}{1-(-3)})=4(\frac{1-(r)^{m+1}}{1-r})$

Simplify.

$-1(1-3^{225})+\frac{1+3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-1+3^{225}+\frac{1}{2}+\frac{3^{225}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\-\frac{1}{2}+\frac{3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3(3^{225})}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\\frac{-1+3^{226}}{2}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{-1+3^{226}}{8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-3^{226}}{-8}=4(\frac{1-(r)^{m+1}}{1-r})\\4\frac{1-9^{113}}{1-9}=4(\frac{1-(r)^{m+1}}{1-r})$