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inna [77]
3 years ago
12

Homework help answering math questions

Mathematics
1 answer:
Margarita [4]3 years ago
4 0
Boys in cool places it’s just amazing James Charles
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Seaside Bike Shop rents bikes for $10 plus 54 per hour. Jack paid $30 to rent a bike. Which equation, when solved for x, gives t
lozanna [386]
Y=54x+10
If he paid $30 it would be
30=54x + 10
4 0
3 years ago
What persent is 3/250 also pls enculde expliantion
Firlakuza [10]
1.2%

3/250 = 0.012

0.012 x 100 = 1.2%
8 0
3 years ago
Read 2 more answers
If angle a = (7x-27) and angle b = (3x + 29) , then find the value of x.
SpyIntel [72]

Answer:

x = 14

Step-by-step explanation:

7x - 27 = 3x + 29

Subtract 3x from both sides;

4x - 27 = 29

Add 27 to both sides;

4x = 56

Divide both sides by 4;

x = 14

6 0
3 years ago
Find the product of z1 and z2, where z1 = 2(cos 80° + i sin 80°) and z2 = 9(cos 110° + i sin 110°)
nekit [7.7K]
ANSWER

z_1 z_2=18( \cos( 190 \degree  )  + i \sin( 190 \degree) )


EXPLANATION

The given complex numbers are;

z_1 = 2( \cos(80 \degree)  + i \sin(80 \degree) )

and


z_2= 9( \cos(110 \degree)  + i \sin(110 \degree) )


Recall the binominal identity for complex numbers in polar form.



z_1 z_2=r_1 r_2( \cos( \theta_1 +\theta_2)  + i \sin(\theta_1 +\theta_2) )



We apply this property to obtain,


z_1 z_2=2 \times 9( \cos( 80 \degree +  110 \degree  )  + i \sin(80 \degree +  110 \degree) )



z_1 z_2=18( \cos( 190 \degree  )  + i \sin( 190 \degree) )

4 0
4 years ago
Read 2 more answers
((MATHS FORM2 CHAPTER 5 CIRCLE)). HELPPPPPPPPPP I WILL MARK AS BRAINLIEST PLEASE SHOW YOUR WORKING :-)
katrin2010 [14]

Answer:

Step-by-step explanation:

strategy:  Find the area of the entire dartboard, then subtracted the inner circle from that whole.    we will have the entire outer circle,  so divide that by 2 for half of it.   Next divide the inner circle by 4 . Then add that to the outer circle answer from above.

whole circle = \pi*20^{2} = 1257.142857 cm^{2}

inner circle = \pi*10^{2} = 314.2857143 cm^{2}

1257.142857 - 314.2857143 = 942.8571427 outer circle

942.8571427 / 2 = 471.4285 ( half of the outer circle)

now find quarter of the inner circle

314.2857143 / 4 = 78.57142855

add the two parts together

78.57142855 + 471.4285  = 549.9999

The shaded regions = 550 cm^{2}

6 0
3 years ago
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