Answer:
Your answer is: 12f + 49g
Simplify each term.
Step-by-step explanation:
Hope this helped : )
The point A is located in quadrant II
The coordinate of the origin is always (0,0)
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
I guess B. That statement is grammatically incorrect.
reflexive postulate of equality
