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3 years ago

14

How is the square root of 343 cubed 7?

2 answers:

Umnica [9.8K]3 years ago

8 0

I don't know what your question means, but 7 cubed is 343, so the cubic root of 343 is 7.

$7^3 = 343$

$\sqrt[3]{343} = 7$

Exponent and root are inverse operations.
If you square 5 to get 25, then when you take the square root of 25 you get 5.
7^3 = 343, so the cubic root of 343 is 7.

Oksanka [162]3 years ago

5 0

The square root of 343 is cubed 7 because 7x7x7 = 343
hope this helps

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Charles is making pumpkin lattes. His recipe calls for 2/3 cup of milk for every eighth cup of pumpkin purée. If Charles is maki

Molodets [167]

Are we assuming that we are using an eight of a cup of pumpkin puree per latte?
If we are then the answer would be 1.042 cups of milk more than puree.

First we have to find out how much puree we are using.
That would be ( 1/8 ) × 5 = 0.125 × 5 = 0.625 cups of puree.
Then we would find how much milk we are using.
That would be ( 2/3 ) × 5 = 0.666666 ( a lot of sixes ) × 5 = 1.666666 ( a lot of sixes ).
To find the difference, you would then have to subtract the amount of puree from the amount of milk.
You would get 1.666666 − 0.625 = 1.0416666 ( also a lot of sixes ). If you are doing this with your own calculator you should get approximately the same number.
Since the number isn't exact you can round up all the sixes to the nearest thousandth. You should get approximately 1.042 cups.
I hope this helped.

7 0

3 years ago

Prove the divisibility of the following numbers: 45^10·5^40 by 25^20

beks73 [17]

For this case we have the following expressions:

$45^{10} * 5^ {40}$ and $25^{20}$

Let:

$45^{10} * 5^ {40}$ (Integer m)

$25^{20}$ (Integer n)

By definition, an integer m is divisible by an integer n if the remainder of the division is 0. That is, there is an integer p such that: $m = n * p$

Rewriting the expression we have:

$25^{20} = 5^{2 * (20)} = 5^{ 40}$

So:

$\frac {45^{10} * 5^{ 40}} {5^{40}} =$

We cancel similar terms:

$45^{10}$

We check:

$45^{10} * 5^{ 40} = 5^{ 40} * 45^{ 10}$

Answer:

If they are divisible

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3 years ago

Maureen walked 3 miles how many feet did she walk

Ostrovityanka [42]

Answer:

15,840 feet.

Step-by-step explanation:

We have been given that Maureen walked 3 miles. We are asked to convert the distance walked by Maureen in feet.

Since we know that 1 mile equals 5,280 feet, so to convert our given distance we will multiply 3 by 5,280.

$\text{Number of feet Maureen walked}=\text{3 miles}\times \frac{5,280\text{ feet}}{\text{Mile}}$

$\text{Number of feet Maureen walked}=3\times 5,280\text{ feet}$

$\text{Number of feet Maureen walked}=15,840\text{ feet}$

Therefore, Maureen walked 15,840 feet.

7 0

3 years ago

Algebra:<br>y+7-2=21<br>so confused, can someone help?

aleksandrvk [35]

Answer:

y+7-2=21

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y+21-5

y=16

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

What’s the differential equation of

worty [1.4K]

Answer:

$y=\frac{1}{x^{2}-6x+13 }$

Step-by-step explanation:

We have given,

$\frac{dy}{dx}=y^{2}(6-2x)$

and initial condition $x=3,\ y=\frac{1}{4}$

Now,

$\frac{dy}{dx}=y^{2}(6-2x)$

Rearranging the variables, we get

$\frac{dy}{y^{2} }=(6-2x).dx$

Applying integration both sides, we get

$\int\ {\frac{dy}{y^{2} } } \,=\int\ {(6-2x).} \, dx$

⇒ $\frac{-1}{y} =6x-\frac{2x^{2} }{2}$

⇒ $\frac{-1}{y}=6x-x^{2} +C$

Putting the initial condition (i.e., $x=3,\ y=\frac{1}{4}$ ), we get

⇒ $-4=6\times3-(3)^{2}+C$

⇒ $-4=18-9+C$

∴ $C=-13$

We have, $\frac{-1}{y}=6x-x^{2} +C$

now putting the value of $C$ in above equation, we get

⇒ $\frac{-1}{y}=6x-x^{2} -13$

⇒ $\frac{1}{y}=-6x+x^{2} +13$

$y=\frac{1}{x^{2}-6x+13 }$

5 0

3 years ago