What is the constant term in the expansion of the binomial (2x + 3)^3

1 answer:

8 0

For (a+b)^3 is:

1a^3+3a^2b+3ab^2+1b^3

8x^2+36x^2+54x+27

So the constant term is b^3=3^3=27

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nikitadnepr [17]

Answer:

a = 6.94

b = 2

Now the whole thing:

6.94 x 102

Check your work:

102 = 100 x 6.94 = 694

Hope this helped!!!

~BBGLUVER

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