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posledela
3 years ago
9

Let U = {1, 2, 3, 4, 5, 6, 7}, A= {1, 3, 4, 6}, and B= {3, 5, 6}. Find the set A’ U B’

Mathematics
1 answer:
Art [367]3 years ago
8 0

Answer:

Step-by-step explanation:

A'={2,5,7}

B'={1,2,4,7}

A'UB'={1,2,4,5,7}

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PLEASE HURRY<br><br> 9x^2 + 64 = 0<br><br> I NEED THE WORK SHOWN IN ORDER TO GET CREDIT
seropon [69]

Answer:

x = ± \frac{8}{3} i

Step-by-step explanation:

subtract 64 from both sides

9x² = - 64 ( divide both sides by 9 )

x² = - \frac{64}{9} ( take the square root of both sides )

x = ± \sqrt{-64/9} = ± \frac{8}{3} i


6 0
3 years ago
Read 2 more answers
I need help asap please
Step2247 [10]

Answer:

Angle A: 30°

Angle B: 60°

Angle C: 90°

Step-by-step explanation:

Hopefully this helps! :)

8 0
2 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

\log_ab=c\iff a^c=b\\\\n\log_ab=\log_ab^n\\\\a^{\log_ab}=b\\\\\log_aa^n=n\\\\\log_{10}a=\log a\\=============================

1.\\y=\left(\dfrac{5^x}{2}\right)^\frac{1}{4}\\\\\text{Exchange x and y. Solve for y:}\\\\\left(\dfrac{5^y}{2}\right)^\frac{1}{4}=x\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\dfrac{(5^y)^\frac{1}{4}}{2^\frac{1}{4}}=x\qquad\text{multiply both sides by }\ 2^\frac{1}{4}\\\\\left(5^y\right)^\frac{1}{4}=2^\frac{1}{4}x\qquad\text{use}\ (a^n)^m=a^{nm}\\\\5^{\frac{1}{4}y}=2^\frac{1}{4}x\qquad\log_5\ \text{of both sides}

\log_55^{\frac{1}{4}y}=\log_5\left(2^\frac{1}{4}x\right)\qquad\text{use}\ a^\frac{1}{n}=\sqrt[n]{a}\\\\\dfrac{1}{4}y=\log(x\sqrt[4]2)\qquad\text{multiply both sides by 4}\\\\y=4\log(x\sqrt[4]2)

--------------------------\\2.\\y=(10^x-5)^\frac{1}{5}\\\\\text{Exchange x and y. Solve for y:}\\\\(10^y-5)^\frac{1}{5}=x\qquad\text{5 power of both sides}\\\\\bigg[(10^y-5)^\frac{1}{5}\bigg]^5=x^5\qquad\text{use}\ (a^n)^m=a^{nm}\\\\(10^y-5)^{\frac{1}{5}\cdot5}=x^5\\\\10^y-5=x^5\qquad\text{add 5 to both sides}\\\\10^y=x^5+5\qquad\log\ \text{of both sides}\\\\\log10^y=\log(x^5+5)\Rightarrow y=\log(x^5+5)

--------------------------\\3.\\y=\log_4(4x^2)\\\\\text{Exchange x and y. Solve for y:}\\\\\log_4(4y^2)=x\Rightarrow4^{\log_4(4y^2)}=4^x\\\\4y^2=4^x\qquad\text{divide both sides by 4}\\\\y^2=\dfrac{4^x}{4}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\y^2=4^{x-1}\Rightarrow y=\sqrt{4^{x-1}}

6 0
3 years ago
Which expression is equivalent to 15p^-4q^-6/-20p^-12q^-3 in simplified from? assume p=/ 0,q=/0
enyata [817]
(15p⁺⁴.q⁻⁶) /(-20p⁻¹².q⁻³). 

Remember that  a⁻ⁿ = 1/aⁿ  and 1/a⁻ⁿ = aⁿ


(-15/4).(p⁻⁴.q⁻⁶)(p⁺¹².q⁺³). 

(-15/20).(p⁻⁴.p¹².q⁻⁶.q³)

Remember aⁿ.aˣ = aⁿ⁺ˣ

(-15/20).(p⁸.q⁻³)

-3/5(p⁸.q⁻³)


3 0
3 years ago
Read 2 more answers
Joslyn wants to buy 4 packs of pens for 12$ each and a pack of pencils for 6$ how much money does she need
Tcecarenko [31]
Just multiply 4*12 and add 6.
answer =54
6 0
3 years ago
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