A. -3x+5+7-4x
-3x-4x+5+7
-7x+12
-7x+12-5x+17
-7x-5x+12+17
-12x+29
B. -5*(x+2)= -5x-10
-6x-1+ (-5x-10)= -6x-5x-1-10=
-11x-11
Bottom-edgeis 10 cm: 2 ft(30.48cm)
Side-edge is 20 cm : 4 ft(60.96cm)
Poster Area needed = (30.48*60.96)=1858cm2
Paper size = 10*20=200cm2
Need papers= 1858/200=9.3 ~10
.: 10 papers is needed for actual poster.
The answer is D. <span>The volume of the sphere is approximately the same as the cube, but the cube has a greater surface area.</span>