<span>Dayson has 1 m2 of wrapping paper, which is 10000 cm2:
1 m = 100 cm
1 m^2 = (100 cm)^2
</span>1 m^2 = 10000 cm^2
<span>The package has a surface area of cm2:
A = 2*(50*20) + </span>2*(50*18) + 2*(18*20)
A = <span>
<span>4520 cm^2
</span></span>The area of the package is less than the area of the wrapping paper (4520 cm^2 < 10000 cm^2<span>). So, Dayson cover the package with the wrapping paper.</span>
Y=5-2x
x^2 + (5-2x)^2 = 25
x^2 + 25-20x+4x^2 = 25
x^2 +4x^2-20x+25=25
5x^2 -20x=0
x=0 and y=5
-x^3 + x^2/3 + 5 - 13/x
I don't know if this is correct
