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Arte-miy333 [17]
3 years ago
12

A 100%increase followed by a 50% decrease

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
6 0
Add the number by once to make an 100% increase because any numbers' 100% is always that number the. to decrease by 50% just divide it by 2
slega [8]3 years ago
3 0

I think is 50% BECAUSE 100 SUBRACTED BY 50 EQUAL TO 50


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One has only one owner and the other have several.
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a study is planned to compare the proportion of men who dislike anchovies with the proportion of women who dislike anchovies. th
e-lub [12.9K]

Answer:

d. No because n·(1 - \hat p) = 8.96 is less than 10

Step-by-step explanation:

Question options;

a. Yes because the sample sizes of both groups are greater than 5

b. Yes, because in both cases n·\hat p > 10

c. Yes, because we know that the population is evenly distributed

d. No, because the n·(1 - \hat p) is less than 10

Explanation;

The given data are;

The number of men in the sample of men, n₁ = 41

The proportion of men who dislike anchovies, \hat p_1 = 0.67

The number of women in the sample of women, n₂ = 56

The proportion of men who dislike anchovies, \hat p_2 = 0.84

The assumptions for an analysis of the difference between means using a T-test are;

1) The data should be from a random sample of the population

2) The variables should be approximately normal (n·\hat p ≥ 10, and n·(1 - \hat p) ≥ 10)

3) The scale of the data is a continuous ordinance scale

4) The sample size should be large

5) The sample standard deviations should be approximately equal

From the requirement for normality, we have;

For the sample of men, n₁·\hat p₁  = 41 × 0.67 = 24.47 > 10

n₁·(1 - \hat p₁) = 41 × (1 - 0.67) = 13.53 > 10

For the sample of women, n₂·\hat p₂  = 56 × 0.84 = 47.04 > 10

n₂·(1 - \hat p₂) = 56 × (1 - 0.84) = 8.96 < 10

Therefore, the for n₂·(1 - \hat p₂), the sample does not meet the requirement for normality

The correct option is d. No because n₂·(1 - \hat p₂) = 8.96 is less than 10

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On the other hand, suppose -4y+2. Then

|-4y+2| = -(-4y+2) \implies 30 = 4y - 2 \implies 4y = 32 \implies \boxed{y=8}

Recall the definition,

|x| = \begin{cases} x & \text{if } x \ge 0 \\ -x & \text{if } x < 0 \end{cases}

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Answer:

Step-by-step explanation:

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<span>Let us see if I understand the question:

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