show that the lines x2-4xy+y2=0 and x+y=3 form an equilateral triangle also find area of the triangle

Mathematics

1 answer:

arlik [135]3 years ago

4 0

Given pair of lines are x² + 4xy + y² = 0

⇒ (y/x) ² + 4 y/x + 1 = 0

⇒ y/x = -4±2√3/2 = -2±√3,

∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle

Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,

The perpendicular distance form origin to x - y = 4 is the height of the

h = 2 √ 2

∵ Area of triangle = h²/√3 = 8/√3

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patriot [66]

Answer:

20%

Step-by-step explanation:

The reason it is 20% is due to the fact that if you put it in a form showing 250/250 = 100/100 and put another proportional rate underneath it showing 200/250 = x/100, you would have to multiply the numerator of the fraction on the left by the denominator of the fraction on the right to get 20000. Now you divide 250 from 20000 and get x for 80, resulting in 80/100 or 80%. All you have to do now is subtract 100-80, which equals 20, resulting in 20%.

Hope that helps!! It's my first time in answering so, ya. ;D goodluck!

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3 years ago

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Greeley [361]

Answer:

the answer is d e and fans f

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3 years ago

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Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a

just olya [345]

Answer:

$P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)$

$=P(Z$

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and $X \sim Bin(n=600, p =0.4)$

And we want this probability:

$P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10$