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Goshia [24]
3 years ago
12

show that the lines x2-4xy+y2=0 and x+y=3 form an equilateral triangle also find area of the triangle

Mathematics
1 answer:
arlik [135]3 years ago
4 0

Given pair of lines are x² + 4xy + y² = 0

⇒ (y/x) ² + 4 y/x + 1 = 0

⇒ y/x = -4±2√3/2 = -2±√3,

∴  The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle

Clearly the pair of lines x² + 4xy +y²  = 0  intersect at origin,

The perpendicular distance form origin to x - y = 4 is the height of the

h = 2 √ 2

∵ Area of triangle = h²/√3 = 8/√3

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What is the greatest common factor and least common multiple of 4 and 10?
rusak2 [61]

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3 0
3 years ago
4-(2x-3)=3 whats the answer
Oxana [17]

Hello there.

Explanation:

↓↓↓↓↓↓↓↓↓↓

4-(2x-3)=3

First, subtract by 4 from both sides.

4-(2x-3)-4=3-4

Second, simplify.

-(2x-3)=-1

Third, divide by -1 from both sides.

\frac{-(2x-3)}{-1}=\frac{-1}{-1}

Fourth, simplify.

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Next, add by 3 from both sides.

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Then simplify.

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Therefore, divide by 2 from both sides.

\frac{2x}{2}=\frac{4}{2}

Finally, simplify.

x=2

<u><em>Answer⇒⇒⇒⇒x=2</em></u>

Hope this helps!

Thank you for posting your question at here on Brainly.

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