Number 19 you are comparing one measurement to another. Since it says 1/2 inch equals 4 ft, we want to find out how many more inches are needed if the given scale was 2/3 = 4 ft. Now lets find a common denominator for both scales stated in inches. We have 2/3 inch and 1/2 inch. Our denominator are the bottom parts of the fraction where we need to find a common factor for the denominator so we can add or subtract fractions. We have a 3 and a 2. You may always use the multiplication between two denominators to find a common factor such as 3 times 2 which equals 6 for both denominators. Now we multiplied the 3 by 2 to get 6 so the top part (numerator needs to be multiplied the the 2 because we changed the bottom part by 2 as well. You should notice that when you reduce your fraction now 4/6 is 2/3. Just a self check example there. As for 1/2 we multiplied a 3 to get 6 for the denominator so we need to multiply the numerator by 3 as well. You now should have 4/6 and 3/6. Since the question asks for how many more inches we need to subtract 4/6 from 3/6 and we get 1/6 inch for our answer.
Answer:
-4, -x^2, x^2, 4
Step-by-step explanation:
As is the case for any polynomial, the domain of this one is (-infinity, +infinity).
To find the range, we need to determine the minimum value that f(x) can have. The coefficients here are a=2, b=6 and c = 2,
The x-coordinate of the vertex is x = -b/(2a), which here is x = -6/4 = -3/2.
Evaluate the function at x = 3/2 to find the y-coordinate of the vertex, which is also the smallest value the function can take on. That happens to be y = -5/2, so the range is [-5/2, infinity).
Answer:
<u><em>30cm</em></u>
Step-by-step explanation:
Given data
When are square is cut diagonally into two parts
The resulting shape is a triangle
hence the area of the square = 50+50 = 100cm^2
The length of each side of the square = √100= 10cm
likewise the diagonal of the square = 10cm
<u><em>Hence the perimeter of the resulting triangle= 10+10+10= 30cm</em></u>
Answer:
Linear Function
Step-by-step explanation:
Let
x----> the time in hours
y----> the total inches of snow on the ground
we know that
The function that best model this situation is the linear function
so
In this problem
----> the y-intercept
substitute
