For this case we have the following functions:
h (x) = 2x - 5
t (x) = 6x + 4
Part A: (h + t) (x)
(h + t) (x) = h (x) + t (x)
(h + t) (x) = (2x - 5) + (6x + 4)
(h + t) (x) = 8x - 1
Part B: (h ⋅ t) (x)
(h ⋅ t) (x) = h (x) * t (x)
(h ⋅ t) (x) = (2x - 5) * (6x + 4)
(h ⋅ t) (x) = 12x ^ 2 + 8x - 30x - 20
(h ⋅ t) (x) = 12x ^ 2 - 22x - 20
Part C: h [t (x)]
h [t (x)] = 2 (6x + 4) - 5
h [t (x)] = 12x + 8 - 5
h [t (x)] = 12x + 3
Hi there!
Unfortunately, the set of ordered pairs does NOT represent a function! This is because there are two of the same x values. In a function, there is one input for every output. In this case, there are two of the same inputs. However, there can be two of the same outputs.
Just to clarify - Not a function
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
Step-by-step explanation:
The sum of the two costs is $52, so we can write ...
x + y = 52
The shoes cost $4 more than the jacket, so we can write ...
x - y = 4
These are your system of equations.
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Subtract the second equation from the first:
(x +y) -(x -y) = (52) -(4)
2y = 48 . . . . . simplify
y = 24 . . . . . . .divide by 2
The cost of the jacket is $24.
The answer is approximately -36
9514 1404 393
Answer:
{5, 10, 15, 20}
Step-by-step explanation:
Multiples of 5 are of the form 5n, where n is an integer. The ones of interest will satisfy ...
0 < 5n < 23
0 < n < 4.6
That is, the multiples of 5 we want are for values of n that are 1 through 4. The set is ...
5 × {1, 2, 3, 4} = {5, 10, 15, 20}
