Answer:
60 inches long are the sides of the pillars.
Step-by-step explanation:
Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.
To find : How many inches long are the sides of the pillars?
Solution :
Refer the attached picture below for Clarence of question.
The volume of the cube is 
Where, a is the side.
The combined volume of the four pillars is 500 ft cubed.
The volume of each cube is given by,

Substitute in the formula to get the side,

![a=\sqrt[3]{125}](https://tex.z-dn.net/?f=a%3D%5Csqrt%5B3%5D%7B125%7D)

We know, 1 feet = 12 inches
So, 5 feet =
inches
Therefore, 60 inches long are the sides of the pillars.
Answer:
Step-by-step explanation:
common difference d=3-1=2
first term a=1
an=a+(n-1)d
2n-1=1+(l-1)2
2n-1=1+2l-2
2n-1=2l-1
l=n
(i used l for number of terms)
number of terms=n

Answer:
11:05
Step-by-step explanation:
Answer:
694 ft²
Step-by-step explanation:
Calculate the area of all 6 walls, noting that the front and back faces are congruent as are the 2 side faces and top/bottom faces
area = 2(13 × 8.5) + 2(11 × 8.5) + 2(13 × 11)
= 221 + 187 + 286 = 694 ft²