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sp2606 [1]
3 years ago
9

Perry currently has $180 dollars and is spending $6 per day nick has no money but is earning $8 each day after how many days wil

l they have the same amount of money
Mathematics
1 answer:
Delvig [45]3 years ago
7 0

Answer:

After 12.86 days Nick and Perry will have the same amount of money

Step-by-step explanation:

Perrie's can be expressed as;

Total amount Perry will have after t days=Initial amount Perry has-Total amount Perry spends

where;

Initial amount that Perry has=$180

Total amount Perry spends=Amount he spends per day×Number of days=(6×t)=6t

Replacing in the expression;

Total amount Perry will have after t days=(180-6t)

Nick's can be expressed as;

Total amount Nick will have after t days=Initial amount Perry has+Total amount Nick earns

where;

Initial amount that Nick has=$0

Total amount Nick earns=Amount he earns per day×Number of days=(8×t)=8t

Replacing in the expression;

Total amount Nick will have after t days=(0-8t)=8t

Equating Total amount Nick will have after t days to Total amount Perry will have after t days;

180-6t=8t

180=(8t+6t)

14t=180

t=(180/14)=12.86 days

After 12.86 days Nick and Perry will have the same amount of money

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The probability that more than 4 weigh more than 20 pounds is:

P(X > 4) = 1 - P(X \leq 4)

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P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

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P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502

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P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106

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P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

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