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4 years ago

Please help i have 4 min

Mathematics

1 answer:

krok68 [10]4 years ago

3 0

$x^2=5^2+8^2\\
x^2=25+64\\
x^2=89\\
x=\sqrt{89}\approx9.4$

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PLEASE ANSWER THIS MATH QUESTION FOR THOSE MATH LOVERS :)

viva [34]

Remark

The general formula for these types of questions is

(x1 + k(x2 - x1) ) , (y1 + k(y2 - y1))

Problem 1 -- Point G

Givens

(x1,y1) is the starting point which in this case is (-3, -3)

(x2,y2) is the ending point which in this case is (6 , -3)

k = 1/4

Sub and solve

(-3 + 1/4(6 - - 3), - 3+ 1/4(- 3 - - 3)

(-3 + 1/4(9) , - 3 + 1/4 (-3 + 3)

(-3 + 9/4, -3 + 1/4(0) )

(-12/4 + 9/4 , -3)

(-3/4 , - 3) Answer

Problem 2 Point F Much harder

Givens

(x1,y1) = (-3 , -1)

(x2,y2) = (6, - 3)

k = 3/4

Sub and solve

(-3 + 3/4(6 - - 3) , -1 + 3/4(-3 - - 1) )

(-3 + 3/4(9) , - 1 + 3/4(-2) )

(-3 + 27/4 , -1 - 6/4 )

(-12/4 + 27/4, -4/4 - 6/4)

( 15/4 , - 10/4) <<<<<< Answer Part B

4 0

3 years ago

Read 2 more answers

Choose one of the factors of x3 − 1331.

Dmitry [639]

Answer A) x-11
Hope this helps!

3 0

3 years ago

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Guysss plsss HEELPPP ME ILL MARK BRAINLIEST PLLLSSSSSS HELP

Vitek1552 [10]

Answer:

$y=-2\,(x-6)^2+246$

with the video game cost of x = $6

This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

$y=ax^2+bx+c$

is given by:

$x_{vertex}=\frac{-b}{2\,a}$

In our case, the quadratic expression that generates the parabola is:

$y=-2x^2+24x+174$

then the x-position of its vertex is:

$x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{-24}{2\,(-2)}\\x_{vertex}=\frac{-24}{-4)}\\x_{vertex}=6$

This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

$y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246$

This value is the highest weekly profit (y = $246).

Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position $(x_{vertex},y_{vertex})$ :