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just olya [345]
3 years ago
6

Plz help have to make this into a mixed number fraction

Mathematics
1 answer:
dmitriy555 [2]3 years ago
4 0
Oh this is easy lol
number 1 is:

2 and 2/3

number 3 is:

2 and 3/5

number 5 is:

3 and 1/6

number 7 is:

3 and 7/8
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In a paint factory, an old conveyer line has filled 20 barrels of paint, and is filling more at a rate of 7 barrels per minute.
vagabundo [1.1K]

It takes 10 minutes for the two lines to have filled an equal number of barrels

Each line will have filled 90 barrels

<em><u>Solution:</u></em>

Let "x" be the number of minutes

<em><u>The old conveyer line has filled 20 barrels of paint, and is filling more at a rate of 7 barrels per minute</u></em>

Thus, a equation is framed as follows:

Old conveyor: 20 + 7(number of minutes)

Old conveyor: 20 + 7x ------- eqn 1

<em><u>A worker just switched on a newer line that can fill 9 barrels per minute</u></em>

Thus, a equation is framed as follows:

New conveyor: 9(number of minutes)

New conveyor: 9x -------- eqn 2

<em><u>In a little while, the two lines will have filled an equal number of barrels.</u></em>

<em><u>Thus, eqn 1 must be equal to eqn 2</u></em>

20 + 7x =9x\\\\9x - 7x = 20\\\\2x = 20\\\\x = 10

Thus it takes 10 minutes for the two lines to have filled an equal number of barrels

<em><u>How many barrels will each line have filled? </u></em>

Substitute x = 10 in any one of equations

Substitute in eqn 2

9x = 9(10) = 90

Thus each line will have filled 90 barrels

8 0
3 years ago
The ratio of the sides of 2 cubes is 2 to 7. If the volume of the smaller cube is 32 u3, then the volume of the larger cube is _
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\bf \qquad \qquad \textit{ratio relations}&#10;\\\\&#10;\begin{array}{ccccllll}&#10;&Sides&Area&Volume\\&#10;&-----&-----&-----\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}&#10;\end{array} \\\\&#10;-----------------------------\\\\&#10;\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\&#10;-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{2}{7}=\cfrac{\sqrt[3]{32}}{\sqrt[3]{v}}\implies \cfrac{2}{7}=\sqrt[3]{\cfrac{32}{v}}\implies \left( \cfrac{2}{7} \right)^3=\cfrac{32}{v}&#10;\\\\\\&#10;\cfrac{2^3}{7^3}=\cfrac{32}{v}\implies v=\cfrac{7^3\cdot 32}{2^3}
5 0
3 years ago
Rajan needs 1 liter of 15% hydrochloric acid solution for an experiment. He checks his storage cabinet, but he only has a 5-lite
yarga [219]

Answer:

<em>Rajan must use </em><em>0.75</em><em> liters of 5% hydrochloric acid solution and </em><em>0.25</em><em> liters of 45% hydrochloric acid solution.</em>

Step-by-step explanation:

Let us assume that, x liters of the 5% hydrochloric acid and y liters of the 45% hydrochloric acid solutions are combined.

As Rajan need total of 1 liter of solution, so

x+y=1

i.e x=1-y --------------------1

As Rajan needs 5% hydrochloric acid and 45% hydrochloric acid to make a 1 liter batch of 15% hydrochloric acid, hence acid content of the mixture of two acids will be same as of the final one, so

0.05x+0.45y=1\times 0.15

i.e 5x+45y=15 -------------2

Putting value of x from equation 1 in equation 2,

\Rightarrow 5(1-y)+45y=15

\Rightarrow 5-5y+45y=15

\Rightarrow 5+40y=15

\Rightarrow 40y=15-5=10

\Rightarrow y=0.25

Putting the value of y in equation 1,

x=1-0.25=0.75

Therefore, Rajan must use 0.75 liters of 5% hydrochloric acid solution and 0.25 liters of 45% hydrochloric acid solution.

5 0
4 years ago
A sandwich shop is ordering apples and grapes to make chicken salad.Apples cost $2.19 per pound and grapes cost $2.60 per pound.
andrew11 [14]

Answer:

Grapes=19.51

Step-by-step explanation:

Apples=$2.19 per pound

Grapes=$2.60 per pound

Apples+Grapes=20 pounds

A+G=20

A=20-G

Equation is

PaA+PgG=35.80

2.19A+2.60G=35.80

2.19(20-G)+2.60G=35.80

43.8-2.19G+2.60G=35.80

43.8-0.41G=35.80

-0.41G=35.80-43.8

-0.41G=-8

Divide both sides by 0.41

G=19.51 pounds

Recall

A=20-G

A=20-19.51

A=0.49 pounds

8 0
3 years ago
Four subtracted from eight is equal to two squared
Scilla [17]
Yes. This is true because 4 subtracted from 8 is 8-4=4. The value you get from subtracting 4 from 8 equals the same value you would get if you were to take the value of 2 and square it. Both equal 4.
4 0
3 years ago
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