3 years ago

Which system of equations has no solutions?

Mathematics

1 answer:

seropon [69]3 years ago

7 0

Answer:

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When the volume of a gas is

Fudgin [204]

Answer: The initial volume is 593.76mL

Step-by-step explanation:

As you do not say anithing about the pressure, i guess that the pressure remains constant.

If the gas is an ideal gas, we have:

P*V = n*R*T

where P is pressure, n is number of moles and R is a constant.

Now, initially we have:

P*Vi = n*R*315°C

finally we have:

P*825mL = n*R*452°C

Now we can take the quiotient of those two equations and get:

(P*Vi)/(P*852mL) = (n*R*315°C)/( n*R*452°C)

Now we have:

Vi/852mL = 315/452

Vi = (315/452)*852mL = 593.76mL

So when we expand the gas at constant pressure, we increase the temperature.

3 0

3 years ago

Evaluate this exponential expression 7 • (6+2)^2 - 3^2=

Lelu [443]

Answer: 441

Step-by-step explanation:

$7*(6+2)^2-3^2$

$7*8^2-3^2$

$7*64-9$

$448-9$

441

3 0

2 years ago

At school, the maximum number of students that can be in a classroom is 21. If there are 16 students signed up for the geometry

nalin [4]

Step-by-step explanation:

Simple

We will subtract

21 - 16 = 5

So 5 more students can join the class

7 0

3 years ago

Someone please help me answer this!!

dybincka [34]

Answer:

17.9 units is the answer

Step-by-step explanation:

points are (-7,-2) and (9,6)

Pythagorean theorem can be written as,

$d=\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\\\d=\sqrt{9-(-7))^2 + (6-(-2))^2}\\\\d=\sqrt{(16)^2+(8)^2} \\\\d=\sqrt{256+64} \\\\d=\sqrt{320} \\\\d=17.88$

Rounding off,

d = 17.9 units

7 0

3 years ago

In the diagram of Triangle ABC: DR Il AC, DB=6, AD=2, and DE=9.Find AC

katen-ka-za [31]

12 because db/ad = 3 and ab = 8
thus de+(de/3) is the answer
12 <- answer

3 0

3 years ago