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yawa3891 [41]
3 years ago
7

Out of a total of 300 animal in a zoo 45 are bird's what percent of the animal in the zoo are bird's

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0
The percentage of birds in the zoo will be 15%
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Joel earns $5.50 an hour and time-and-a-half for overtime. how much does he earn for a 44.5-hour week?
vova2212 [387]
The expression which can be used to solve this problem is 5.50h + 1.5h. 

Since the given data is 44.5 hour week, all we need to do is substitute the given data to the expression. Since it takes 56 hours a week for a complete office/working hour without overtime, Joel's 44.5 hour week means he did not have overtime hours. Therefore the solution is,

5.50(44.5) = 244.75 Dollars.
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3 years ago
Part 2:
anastassius [24]

Answer:

Whats the question?

Step-by-step explanation:

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16. A company collected funds for charity from employees. The amount donated by some employees on the first day is as
ivolga24 [154]

Answer: Median is the best measure of central tendency best represents the data.

Value of median= 15

Step-by-step explanation:

The given data : $10, $20, $15, $100, $10, $15, $10.

We observe that the above data has an outlier in it .

$100 is an extremely large value as compare to the other values in the data.

It means the data contains outlier.

Commonly , mean is the best measure of the central tendency.

We know that , when there is an outlier in the data , we prefer Median over Mean to measure the central tenancy of the data.

So for the given data set ,

Median is the best measure of central tendency best represents the data.

To find median , first arrange data in an order , we get

10 , 10 , 10 , 15 , 15 , 20 , 100

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So Median= Middle-most number=  15

Hence, the median of data = 15

5 0
3 years ago
What is 4m=68 as a equation
Blababa [14]
4 * m = 68
÷ 4     ÷ 4
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Describe what a frequency table is what is used for
aev [14]

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A frequency table is records the number of observations falling in each interval. They are useful for analyzing data and for screening data for data entry errors.

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