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Travka [436]
3 years ago
10

What is the value of sin x

Mathematics
1 answer:
maria [59]3 years ago
4 0
SinX = <span>Opposite / Hypotenuse</span> =12/13

Answer: C).
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How do you complete this One-Step equation?<br>5 1/2 + p = 6
dalvyx [7]

5 1/2 + p = 6

subtract 5 /12 from each side

5 1/2  - 5 1/2+ p = 6 - 5 1/2

p = 6 - 5 1/2

borrow from the 6

p = 5 2/2 - 5 1/2

p = 1/2

8 0
3 years ago
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In simplified exponential notation, the expression a²·a -3·a=<br><br> A 1/a<br> B 0<br> C 1
dalvyx [7]
Answer a^3-3a

a^2 times a = a^3 you add exponents
4 0
3 years ago
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Which equation can be used to solve for x in the parallelogram below?
densk [106]

Answer:

B. (3x - 12)° = (2x + 8)°

Step-by-step explanation:

This equation can be used to solve x.

3x - 12 = 2x + 8

3x - 2x = 12 + 8

x = 20°

-------------------------------------------------------------------

Verification:

3(20) - 12 = 2(20) + 8

60 - 12 = 40 + 8

48° = 48°

6 0
3 years ago
Sue had 5 identical bags of candy to share with the crew. Twenty-five pieces of candy disappeared. Ted had 4 bags with the same
inna [77]

Answer:

Each bag originally had 35 pieces of candy

Step-by-step explanation:

Since the bags are identical, Let them Number of candies in each bag sue had be x. Thus, she had 5x candies. Since she lost 25 pieces, then she now has;

5x - 25 candies left.

We are told that Ted had 4 bags with the same number of candies like Sue had. Thus, he has 4x candies.

He mysteriously found 10 additional pieces. Total Ted now has is;. 4x + 10

Finally, we are told that Sue and Ted now have an equal number of candies.

Thus;

5x - 25 = 4x + 10

Rearranging, we have;

5x - 4x = 25 + 10

x = 35

Thus, each bag originally had 35 pieces of candy

3 0
3 years ago
Does anyone know this answer??
Aleonysh [2.5K]

For this case we have the following equation:

(2x + 3) ^ 2 + 8 (2x + 3) + 11 = 0

Let u = 2x + 3

We have:

u ^ 2 + 8u + 11 = 0

By definition, given an equation of the form ax ^ 2 + bx + c = 0

The quadratic formula, to find the solution can be written as:

x = \frac{-b+/-\sqrt{b ^ 2-4 (a) (c)} }{2(a)}

In this case we have:

a = 1\\b = 8\\c = 11

Substituting in the quadratic formula we have:

See attached image

Answer:

Option B

8 0
3 years ago
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