Y=1/x is a reciprocal function & its shape is a special hyperbola with one branch located in the 1st Quadrant and the second in the 3dr Quadrant and both are symmetric about the origin O.
If a> 1 → y=a/x and the 2 branches are equally stretched upward & downward
about the center O.
If 0 < a < 1→y =a/x, the 2 branches are equally stretched downward and upward about the center O.
If a<0, then the 2 legs are in the 2nd and 4th Quadrant respectively
Hello there! The answer to your question is a = 4.
To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.
Our first step is to add 4 to both sides so the 4 cancels out on the left side.
-4+4 + 4a = 12+4
4a = 16
Next, we divide both sides by 4 to finish isolating a.
4/4a = 16/4
a = 4
Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.
-4 + 4(4) = 12
-4 + 16 = 12
12 = 12
Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)
Answer:
Explanation:
We have:
(
2
x
+
3
)
(
4
x
2
−
5
x
+
6
)
Now let's distribute this piece by piece:
(
2
x
)
(
4
x
2
)
=
8
x
3
(
2
x
)
(
−
5
x
)
=
−
10
x
2
(
2
x
)
(
6
)
=
12
x
(
3
)
(
4
x
2
)
=
12
x
2
(
3
)
(
−
5
x
)
=
−
15
x
(
3
)
(
6
)
=
18
And now we add them all up (I'm going to group terms in the adding):
8
x
3
−
10
x
2
+
12
x
2
+
12
x
−
15
x
+
18
And now simplify:
8
x
3
+
2
x
2
−
3
x
+
18Step-by-step explanation:
Answer:
x^2/400 + x^2/625
(x-0)^2/400) +(y-0^2/625)
x^2=400
X=sqrt. 400
x = 20
y^2=625
y = sqrt. 625
y= 25
a^2-c^2=b^2
sqrt 400-625 = c
20-25=c
The correct answer is c=-5
(-5,0)
(5,0)
Step-by-step explanation:
Answer:
(-18,4) is 16 units below (-18,20). hope this helps
Step-by-step explanation:
- Zombie
