Answer:
i)
- <em>DA is diameter and AX is tangent to circle</em>
<u>Your answer is correct</u>
ii)
<u>Given m∠BAX = 42° and ∠DAB is complementary with BAX ⇒ </u>
<u>DC = BC ⇒ intercepted arcs are same ⇒ </u>
<u>mDC = mCB ⇒ mDCB = ∠DAB = 48° ⇒ </u>
- m∠CDB = m∠BDC = 1/2*48 = 24°
iii)
∠CBA
<u>∠CBA is supplementary with ∠ADC as opposite angles of cyclic quadrilateral (∠ADB = ∠BAX = 42°)</u>
- m∠ADC = m∠ADB + m∠CDB = 42° + 24° = 68°
- m∠CBA = 180° - m∠ADC = 180° - 68° = 112°
∠BAE
EA║CB and AB is transversal ⇒ CBA and BAE are supplementary angles:
- m∠BAE = 180° - 112° = 68°
∠DCE
- m∠DCB = 180° - m∠DAB = 180° - 48° = 132°
- m∠BCE = 180° - m∠BAE = 180° - 68° = 112°
- ∠DCE = 132° - 112° = 20°
Answer:
12√5
Step-by-step explanation:
According to the attached sketch, there are 2 triangles which we need to focus on, triangle A (in yellow) and triangle B (In red).
If you look at triangle A, we notice that X is the hypotenuse of triangle A. This means that X must be the largest length in triangle A, hence we can say that x must be greater than 24 (or 24 < x)
Now look at triangle B, in this case, they hypotenuse is 30 and x is the length of one of the sides. This means that x must be shorter than the hypotenuse (i.e x < 30)
from the 2 paragraphs above, we can see now that we can assemble an inequality in x
24 < x < 30
If we look at the choices, we can immediately ignore 33 because x must be less than 30,
working out the choices, we find that the only choice which falls into the range 24<x<30 is the 2nd choice 12√5 (= 26.83) (which is the answer)
The last 2 choices give values smaller than 24 and are hence cannot be the answer
No, Shani is not right.
The 1st customer to get popcorn and apple juice is the 18th customer.
She missed that 18 is a common multiple of 6 & 9
Your answer will be <span>9 Months 15 days hope this helps</span>
Answer:
To dilate the figure by a factor of 2, I will multiply the x and y-value of each point by 2. I plotted all the new points to find the new triangle. To dilate the figure by a factor of 2, I will multiply the x and y-value of each point by 2.
The picture below shows a dilation with a scale factor of 2. This means that the image, A', is twice as large as the pre-image A. Like other transformations, prime notation is used to distinguish the image fromthe pre-image.
Step-by-step explanation:
ur welcome