The average value of the function f(x) = 3x^2 is 3 on the inetrval [-3, 3].
According to the given question.
We have a function.
F(x) = 3x^2
Since, we know that " the average value of a function is found by taking the integral of the function over the interval and dividing by the length of the interval".
Here, the given interval is [-3, 3]
Therefore, the length of the interval = 3 - (-3) = 3 + 3 = 6
Now, the average value of the given function f(x)
![= \frac{1}{6} [\frac{x^{3} }{3} ]_{3} ^{-3}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B1%7D%7B6%7D%20%5B%5Cfrac%7Bx%5E%7B3%7D%20%7D%7B3%7D%20%5D_%7B3%7D%20%5E%7B-3%7D)
= 2(27)/18
= 27/9
= 3
Hence, the average value of the function f(x) = 3x^2 is 3 on the inetrval [-3, 3].
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A = L * W
A = 45
L = 2W + 1
45 = W(2W + 1)
45 = 2W^2 + W
2W^2 + W - 45 = 0
(2W - 9)(W + 5) = 0
W + 5 = 0
W = -5...not this one because it is negative
2W - 9 = 0
2W = 9
W = 9/2
W = 4.5 <=== the width is 4.5 ft
L = 2W + 1
L = 2(4.5) + 1
L = 9 + 1
L = 10 <=== the length is 10 ft
Step-by-step explanation:
No correlation
Answer:
a)
b)
Step-by-step explanation:
From the question we are told that
The Function
Generally the differentiation of function f(x) is mathematically solved as
Therefore
Generally critical point is given as
Generally the maximum and minimum x value for critical point is mathematically solved as
Where
Maximum value of x
Minimum value of x
Therefore interval of increase is mathematically given by
Therefore interval of decrease is mathematically given by
Generally the second differentiation of function f(x) is mathematically solved as
Generally the point of inflection is mathematically solved as
Therefore inflection points is given as
a)Generally the concave upward interval X is mathematically given as
b)Generally the concave downward interval Y is mathematically given as
2p + 2 = 24
2p = 22
p = 22/2
p = 11
