Answer:
Length of the rectangle = 9.58 feet and width = 27.14 foot
Step-by-step explanation:
Let the length of the rectangular area is = x feet
and the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 260
y = 
-------(1)
Cost to fence the three sides = $3 per foot
Therefore cost to fence one length and two width of the rectangular area
= 3(x + 2y)
Similarly cost to fence the fourth side = $14 per foot
So, the cost of the remaining length = 14x
Total cost to fence = 3(x + 2y) + 14x
Cost (C) = 3(x + 2y) + 14x
C = 3x + 6y + 14x
= 17x + 6y
From equation (1)
C = 
Now we take the derivative,
C' = 17 - 
To minimize the cost of fencing,
C' = 0
17 - = 0
= 17
x = 9.58 foot
and y = 
y = 27.14 foot
Answer:
A, C
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
the ∠A is adjacent (adj) to AB and opposite (Opp) of BC and AB is the hypotenuse (Hyp) of the triangle
which one of the above trig functions fits that?
sin(Ф) = BC / AC is sin(Ф)= Opp / Hyp , so choice A) works
cos(Ф) = BC / AC is not cos(Ф) = Opp / Hyp so choice B) does not work
cos(Ф) = BA / AC is cos(Ф) = Adj / Hyp so choice C) works
AC / BC is just a ratio it's not the angle , so D) doesn't work
Answer:
20$ each visit
Step-by-step explanation
Divide 40 by 2 for her 2 visits to the bank
<em>Final Answer: </em>
I believe it could be 19.5
Answer:
6 square units
Step-by-step explanation:
In oder to do this, you need graph paper to make it easier and then mark your graph paper with the quadrants.
I got 3 unites for the height and 4 units for the base
4 x 3 = 12 square units
however the formula for a triangle is Ab/2
so divide 12/2 = 6
So its 6 square units
