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I am Lyosha [343]
3 years ago
14

Consider that point A is located at (x, y) in Quadrant I of the coordinate plane. In which quadrant is point B with coordinates

(-x, -y)located?
A) Quadrant I
B) Quadrant II
C) Quadrant IV
D) Quadrant III
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
C) quadrant IV

it is saying I need more echaractes but I wrote the answer so I am writing this
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Answer:

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Find the equation of the sphere in standard form centered at (−6,10,5) with radius 5.
Dovator [93]

Answer:

The equation of the sphere in standard form is

x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0

Step-by-step explanation:

<u>Step 1</u>:-

The equation of the sphere having center and radius is

(x-h)^{2} +(y-k)^{2} +(z-l)^{2} = r^{2}

Given centered of the sphere is (-6,10,5) and radius r=5

(x-(-6))^{2} +(y-10)^{2} +(z-5)^{2} = 5^{2}

on simplification,we get

using (a+b)^{2} =a^{2} +2 a b+b^{2}

using (a-b)^{2} =a^{2} -2 a b+b^{2}

simplify , we get

x^{2} +y^{2}+z^{2} +12 x-20 y-10 z+136=0

8 0
3 years ago
Using the following image, solve for SR. Look at the image closely.
iren [92.7K]

Step-by-step explanation:

I assume

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4 0
2 years ago
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3 years ago
A circular swimming pool has a diameter of the 26 feet.
kherson [118]
Hey there! :)

The formula for finding area of circles is: π · r²

<em>Remember that radius is half the diameter. To find radius when the diameter is given, divide by 2</em>

d = 26

26 ÷ 2 = 13
_____________________________________________________________

π · r²

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