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I am Lyosha [343]
3 years ago
14

Consider that point A is located at (x, y) in Quadrant I of the coordinate plane. In which quadrant is point B with coordinates

(-x, -y)located?
A) Quadrant I
B) Quadrant II
C) Quadrant IV
D) Quadrant III
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
4 0
C) quadrant IV

it is saying I need more echaractes but I wrote the answer so I am writing this
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36 centimeters

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Apply the rules for order of operations to simplfy 2 3-4 (5x4).
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Each side of a square is increasing at a rate of 6cm/s. At what rate is the area of the square increasing when the area of the s
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Area of a square = length²
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The question is in the screenshot attached. Thank you!
Rzqust [24]

Answer:

Domain: -4 < x < 4

Zeros: (-2, 0), (0, 0) and (2, 0)

The function is positive if: 0 < x < 2

The function is negative if: -4 < x < 0 and 2 < x < 4

Step-by-step explanation:

Domain of the function are those x values where the function is defined, For this case, -4 < x < 4

Zeros of a function are those x values where y = 0, that is, the graph intersect x-axis. For this case, the points are: (-2, 0), (0, 0) and (2, 0)

The function is positive if the graph o the function is above x-axis. For this case, the function is positive at the interval (0, 2)

The function is negative if the graph o the function is below x-axis. For this case, the function is negative at the intervals (-4, 0) and (2, 4)

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