Consider that point A is located at (x, y) in Quadrant I of the coordinate plane. In which quadrant is point B with coordinates
1 answer:
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Answer:
Step-by-step explanation:
Sin(30) / X = Sin(45) / 12
use algebra to isolate X
1 / X = [ Sin(45) / 12 ] / Sin(30)
flip both sides
X = Sin(30) / [Sin(45) /12 ]
invert the denominator on the right side
X = Sin(30) * 12/ Sin(45)
Do you know what Sin(30) is off the top of your head?
and also Sin(45) ?
these are worth remembering... and you can b/c they are just
sin(0) = 0/2
sin(30) = 1 / 2
sin(45) = /2
sin(60)= / 2
sin(90) = / 2 (aka 1)
note the numerators just counts up 0, 1, 2, 3, 4 :)
Cos works the same way but counts from 90° back to 0 but exactly like sin other wise, hence why Cos and Sin both = /2 at 45 °
anyway
X = 1 / 2 * 12/ /2
X = 3
A=3
B= 2
:) nice , huh