(x1,y1) = (-2,7)
m = -5
(x,y) = (a,2)
Forming the equation,
(y-y1) = m(x-x1)
y - 7 = -5[x - (-2)]
y - 7 = -5x - 10
y + 5x = -3
Putting the values of (x,y) we get,
2 + 5a = -3
5a = -5
a = -1
Answer:

Step-by-step explanation:
We can write the equation of a line in 3 different forms including slope intercept, point-slope, and standard depending on the information we have. We have two standard form equations which we will get a slope and a y-intercept from. We will convert each to slope intercept form to get the information. We will then write a new slope-intercept equation and convert to standard form.
3x-5y=7 has the same slope as the line. Let's convert.


The slope is
.
2y-9x=8 has the same y-intercept as the line. Let's convert.


The y-intercept is 4.
We take
and b=4 and substitute into y=mx+b.

We now convert to standard form.

For standard form we need the coefficients of x and y to be not zero or fractions. We need integers but the coefficient of x cannot be negative. So we multiply the entire equation by -5 to clear the denominators.

Answer:
20) yes
21) -1
22) 1
23) -4
Step-by-step explanation:
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