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3 years ago

Help please!!! asap! 10 points!

Mathematics

1 answer:

Anna11 [10]3 years ago

5 0

Answer:

Fr^2/Gm_2=m_1

Step-by-step explanation:

What you do first is you have to cross-multiply so f*r^2 and 1*gm_1m_2 to get

Fr^2=Gm_1m_2. Next you will divide Gm_2 from both sides to get

Fr^2/Gm_2=m_1 as your answer.

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The line shown represents the amount of money Ben owes on his lunch account.

nasty-shy [4]

Answer:

y=2x-1

Step-by-step explanation:

Remeber to put no spaces on the test

and it is this answer bc he owes one dollar evryday and owing is negative

7 0

3 years ago

8 times the difference of 2 and a number

ankoles [38]

Hello There!

It would be 8(2-x)

Hope This Helps You!
Good Luck :)

- Hannah ❤

3 0

3 years ago

Read 2 more answers

Hhelp pls lol i don't understand

sladkih [1.3K]

Answer:

m∠1= 80

m∠2= 100

m∠3= 80

Step-by-step explanation:

Given: m∠1= 2x +40

m∠2= 2y +40

m∠3= x +2y

m∠1 +m∠2= 180 (adj. ∠s on a str. line)

2x +40 +2y +40= 180

2x +2y+ 80= 180

2x +2y= 180 -80

2x +2y= 100

2(x +y)= 100

x +y= 100 ÷2

x +y= 50 -----(1)

m∠1= m∠3 (vert. opp. ∠s)

2x +40= x +2y

2x -x +40= 2y

x= 2y -40 -----(2)

Substitute equation (2) into (1):

2y -40 +y= 50

3y= 50 +40

3y= 90

y= 90 ÷3

y= 30

Substitute y= 30 into equation (2):

x= 2(30) -40

x= 60 -40

x= 20

m∠1

= 2x +40

= 2(20) +40

= 40 +40

= 80

m∠2

= 2y +40

= 2(30) +40

= 60 +40

= 100

m∠3

= x +2y

= 20 +2(30)

= 20 +60

= 80

Alternatively, since m∠1= m∠3,

m∠3

= m∠1 (vert. opp. ∠s)

= 80

5 0

3 years ago

Write a quadratic equation that can be solved by factoring. Solve your equation and show and explain all your work.

miv72 [106K]

Answer:

An example of a quadratic equation is:

${x}^{2} + 5x + 6 = 0$

Step-by-step explanation:

This answer follows the standard form for a quadratic equation:

$a {x}^{2} + bx + c = 0$

To solve this equation you do the following:

x^2 + 5x + 6 =0

The factors that can be added to get *5* and multiplied to get *6* are 3 & 2.

Therefore the new equation would be:

x^2 +3x + 2x + 6 = 0

group the terms: (x^2 +3x) (+2x + 6) = 0

factorize: x (x + 3) 2 (x + 3) = 0

therefore: (x + 2) (x + 3) =0

x = -1 x =-3

4 0

2 years ago

Read 2 more answers

Can anyone help with 13 14 and 15 anything helps!!!

Luda [366]

13. The midpoint divides the segment into two equal parts. That is

BC = (1/2)·AC = (1/2)·(8x -20)

BC = 4x -10

Since you are told the other half is 3x -1, the two halves being equal tells you

... AB = BC

... 3x -1 = 4x -10

... x = 9 . . . . . add 10-3x

Then the measures of AB and BC are 3·9 - 1 = 4·9 -10 = 26.

BC = 26

The problem statement is not clear as to the desired form of the answer—whether it is to be in terms of x, or a number.

14. Same deal as the previous problem. The halves of the bisected segment are equal, giving you an equation that can be solved for x.

... CG = GD

... 5x -1 = 7x -13

... 12 = 2x . . . . . . . . . add 13-5x

... x = 6 . . . . . . . . . . divide by 2

Now you have a value of x that you can use to find the length of EF.

... EF = 6x - 4 = 6·6 - 4 = 32

The parts of EF add to give its total length, so

... EG + GF = EF

... EG + 13 = 32

... EG = 19

15. Once again, the parts of a line segment add to give the whole.

... RS + ST = RT

... (2x -4) + (4x -1) = (8x -43)

... 38 = 2x . . . . . . . . . . . . . . . . add 43-6x

... x = 19

Since R is the midpoint of QS, RS will be half the length of QS. The length of RS is 2x -4 = 2(19) - 4 = 34. Then the length of QS is 2·34 = 68.

QS = 68

_____

To help check our work, we can find the lengths of the other segments in the diagram. ST = 4x - 1 = 75; RT = 8x - 43 = 109. So, we have ...

... QR : RS : ST = 34 : 34 : 75 . . . with QS = 68 and RT = 109.

5 0

3 years ago