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Liula [17]
3 years ago
9

Can some one answer part B have to have it turned in by Monday ??????

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Have u been doing anything with Pythagorean theorem? i belive that is what u have to do

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Find the next three numbers in the pattern 2, 3, 5, 8, ? ? ?
kompoz [17]

9,11,14

the pattern is add one then add two then add three

7 0
3 years ago
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20 POINTS<br> How do you find the interquartile range
kari74 [83]

Answer:

To find the interquartile range (IQR), ​first find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

Step-by-step explanation:

(Khan Academy)

3 0
3 years ago
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Calculate the volume of each diagrams.
wariber [46]

The volume of the solid objects are 612π in³ and 1566πcm³

<h3>Volume of solid object</h3>

The given objects are composite figures consisting of two shapes.

The volume of the blue figure is expressed as;

Volume = Volume of cylinder + volume of hemisphere

Volume = πr²h + 2/3πr³

Volume =  πr²(h + 2/3r)

Volume =  π(6)²(13+2/3(6))

Volume = 36π(13 + 4)

Volume = 612π in³

For the other object

Volume = Volume of cylinder + volume of cone

Volume = πr²h + 1/3πr²h

Volume =  π(9)²(15) + 1/3π(9)²(13)

Volume=  81π (15+13/3)
Volume= 1566πcm³

Hence the volume of the solid objects are 612π in³ and 1566πcm³

Learn more on volume of composite figures here: brainly.com/question/1205683

#SPJ1

8 0
2 years ago
Please help answer A and B
Goshia [24]

Answer:

the answer is A

Step-by-step explanation:

4 0
3 years ago
You roll two standard number cubes. What is the probability that the sum is odd, given than one of the number cubes shows a 1?
Virty [35]
 It's not specified whether 1 is the 1st or 2nd roll: HOWER:

The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:

P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2

NOW if the 2nd Roll is "1", it 's still 1/2

6 0
3 years ago
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