Answer:
The correct answer is option (E)
Step-by-step explanation:
Solution to the question
Let us recall from given question that,
H0:p=0.80
Ha:p≠0.80 (which is the two tailed test)
For the p-value we have,
P-value: Let us assume that the null hypothesis is true, then the probability of observing the sample statistics or the more extreme,
Therefore if p= 0.80, the probability of observing or detecting proportion of samples is of at least 0.84 or at most 0.76 is 0.273.
The answer is D.
y = x + 1 = 4 + 1 = 5
y = 1/2x + 3 = 1/2(4) + 3 = 2 + 3 =5
9.4 units apart, I don’t know why they me you put 20 words it’s stupid
Answer:
The probability that five cars will arrive during the next thirty minute interval is 0.0127.
Step-by-step explanation:
Let <em>X</em> = number of cars arriving at Sami Schmitt's Scrub and Shine Car Wash.
The average number of cars arriving in 20 minutes is, 8.
The average number of cars arriving in 1 minute is,
.
The average number of cars arriving in 30 minutes is,
.
The random variable <em>X</em> follows a Poisson distribution with parameter <em>λ</em> = 12.
The probability mass function of <em>X</em> is:

Compute the probability that 5 cars will arrive in 30 minutes as follows:



Thus, the probability that five cars will arrive during the next thirty minute interval is 0.0127.