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zimovet [89]
3 years ago
8

Rhonda has 25 coins in her pocket. all of the coins are either dimes or nickels. if rhonda has a total of $2.30, how many dimes

does she have

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0
Rhonda has 25 coins in her pocket. all of the coins are either dimes or nickels. if rhonda has a total of $2.30, how many dimes does she have

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Annie, Brianna & Carly are selling fruit boxes to raise money for their soccer team. All together the girls have sold 105 bo
GaryK [48]

Step-by-step explanation:

Annie = x

Brianna = y

Carly = z

Now,

x + y + z = 105 ...(1)

Carly has sold ten more than three times Brianna's sales.

z = 10 + 3y ...(2)

Brianna sold five more than Annie.

y = 5 + x ...(3)

Now,

z = 10 + 3y

z = 10 + 3(5 + x)

z = 10 + 15 + 3x

z = 25 + 3x

Now,

x + y + z = 105

x + (5 + x) + 25 + 3x = 105

5x + 30 = 105

5x = 105 - 30

5x = 75

5x/5 = 75/5

x = 15

So,

y = 5 + x

y = 5 + 15

y = 20

Now,

z = 25 + 3x

z = 25 + 3(15)

z = 25 + 45

z = 70

Thus,

Annie Sold 15 boxes

Brianna Sold 20 boxes

Carly Sold 70 boxes

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2 years ago
Describe in detail how you would plot the value 2 3/8 on a number line
malfutka [58]
Between 2 and 3, after the 2 1/4 point, but before the halfway point.
5 0
3 years ago
Where are you were a problem that can be described by the division expression 9 1/3÷2 3/4 use complete sentences in your answer
svp [43]

Answer:

365 days you got it you got it

Step-by-step explanation:

3 0
3 years ago
The temperature one morning in Shasta was LaTeX: -12^\circ F− 12 ∘ F. By the afternoon, the temperature had risen LaTeX: 8^\circ
Vlad [161]

Answer:

The Temperature in the afternoon was -4\° F.

Step-by-step explanation:

Given:

Temperature in the morning = -12\° F

Rise in temperature = 8\° F

We need to find the temperature in the afternoon.

Solution:

Now we know that;

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framing in equation form we get;

temperature in the afternoon = -12\° F+8\° F=-4\° F

Hence the Temperature in the afternoon was -4\° F.

3 0
2 years ago
Question 3 (4 MARKS) Find the equation of the tangents to the curve of the function with rule y = x^2 at the points where x = a
Arte-miy333 [17]

Answer:

(0 , -a²)

Step-by-step explanation:

tangent at x = a and x = -a

y = x²     (a , a²) and (-a , a²) must be on the curve and tangent to curve

gradient dy/dx = 2x

slope (m) at x = a is <u>2a</u>     and slope (m') at x=-a is<u> -2a</u>

line1: (y - a²) / (x - a) = 2a

        y - a² = 2a (x - a)                           y = 2ax - a²   ... (1)

line2: (y - a²) / (x + a) = - 2a                   y = -2ax- a²   ... (2)

(1) - (2): 4ax = 0       a≠0    x = 0

y = - a²

I wish I did it right, or ....

3 0
3 years ago
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