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zimovet [89]
3 years ago
8

Rhonda has 25 coins in her pocket. all of the coins are either dimes or nickels. if rhonda has a total of $2.30, how many dimes

does she have

Mathematics
1 answer:
USPshnik [31]3 years ago
3 0
Rhonda has 25 coins in her pocket. all of the coins are either dimes or nickels. if rhonda has a total of $2.30, how many dimes does she have

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Solve the inequality. Graph the solution on a number line.
Leya [2.2K]

Answer:

x is bigger than or equal then 5

also known as x>5 but with a line under the >

Step-by-step explanation:

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4 0
3 years ago
the length of a rectangle is 5 times as long as its breadth and its area is 1620 m² find area of square whose perimeter is equal
Rus_ich [418]

Answer:

Area of the square is 2916 m^{2}.

Step-by-step explanation:

Let the breadth of the rectangle be represented by w. So that;

length of rectangle = 5w

Area of rectangle = length x breadth

                             = 5w x w

1620 = 5w^{2}

divide through by 5 to have,

w^{2} = 324

w = \sqrt{324}

   = 18

Thus, the breadth of the rectangle is 18 m.

length = 5 w = 5 x 18

           = 90 m

The length of the rectangle is 90 m.

Perimeter of the rectangle = 2(l + w)

                                  = 2( 90 + 18)

                                  = 216 m

Perimeter of a square = 4l

where l is the length of its side.

Given that the perimeters of the rectangle and square are equal, then;

4l = 216

l = \frac{216}{4}

 = 54

length of the side of square is 54 m.

Therefore,

Area of square = l^{2}

                         = 54^{2}

                        = 2916

Area of the square whose perimeter is equal to that of the rectangle is 2916 m^{2}.

6 0
3 years ago
Instructions: Find the lengths of the other two sides of the isosceles right triangle below.
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Given:

The ratio of 45-45-90 triangle is x:x:x\sqrt{2}.

The hypotenuse of the given isosceles right triangle is 7\sqrt{2}.

To find:

The lengths of the other two sides of the given isosceles right triangle.

Solution:

Let l be the lengths of the other two sides of the given isosceles right triangle.

From the given information if is clear that he ratio of equal side and hypotenuse is x:x\sqrt{2}. So,

\dfrac{x}{x\sqrt{2}}=\dfrac{l}{7\sqrt{2}}

\dfrac{1}{\sqrt{2}}=\dfrac{l}{7\sqrt{2}}

\dfrac{7\sqrt{2}}{\sqrt{2}}=l

7=l

Therefore, the lengths of the other two sides of the given isosceles right triangle are 7 units.

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