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Nataly [62]
3 years ago
10

Solve: V = 1/3Bh for h

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
<span>If you would like to solve the equation </span>V = 1/3 * B * h for h<span>, you can use the following two steps:

</span>V = 1/3 * B * h      /*3
<span>3 * V = B * h         /B
h = 3 * V / B

The correct result would be </span>h = 3 * V / B<span>.
</span>
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Halp me plz i stuck for so long (its part b)
vovangra [49]

The school can expect to raise 1500p for charity.

<u>Explanation:</u>

(a)

The possibility space is solved in the image attached.

(b)

20p for each player

30p for lollipop

Number of people = 120

Charity amount = ?

Out of 12 outcomes, the probability of getting 7 is 3

So, probability of getting 7 for 120 people = \frac{3}{12} X 120

                                                                 = 30

Money earned from the players = 20p X 120

                                                 = 2400p

Cost of 30 lollipops = 30p X 30

                              = 900p

Money received for charity = 2400p - 900p

                                         = 1500p                                  

Therefore, the school can expect to raise 1500p for charity.

7 0
3 years ago
Please help &lt; &lt;&lt;&lt;&lt;&lt;&lt;&lt;&lt;33333333 TYY<br> -20 -8 + (-12)
Montano1993 [528]

Answer:

-30

Step-by-step explanation:

-20-8=-28

-28-12

=-30

5 0
2 years ago
Which expression is NOT equivalent to (6x + 10)? A.3x + 5 B.1/2(6x) + (10) C.6/2x+10/2 D.3x + 10 -------------------------------
Vadim26 [7]

Answer:

A, C

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the mean, median, and mode for 12, 9, 17, 15, 12, 13
Stels [109]
Mean:13 Median:12.5 Mode:12
8 0
3 years ago
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Find f such that the given conditions are satisfiedf’(x)=x-4, f(2)=-1
kicyunya [14]

Given:

f^{\prime}\left(x\right)=x-4,\text{ and}f\left(2\right)=-1

To find:

The correct function.

Explanation:

Let us consider the function given in option D.

f(x)=\frac{x^2}{2}-4x+5

Differentiating with respect to x we get,

\begin{gathered} f^{\prime}(x)=\frac{2x}{2}-4 \\ f^{\prime}(x)=x-4 \end{gathered}

Substituting x = 2 in the function f(x), we get

\begin{gathered} f(2)=\frac{2^2}{2}-4(2)+5 \\ =2-8+5 \\ =-6+5 \\ f(2)=-1 \end{gathered}

Therefore, the given conditions are satisfied.

So, the function is,

f(x)=\frac{x^{2}}{2}-4x+5

Final answer: Option D

6 0
2 years ago
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