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2 years ago

What is the value of the expression, written in standard form?

Mathematics

2 answers:

Pavel [41]2 years ago

6 0

Answer:

I agree with the person above me the that correct answer is 200

Step-by-step explanation:

I also just did the question

I hope this helps you!!

Studentka2010 [4]2 years ago

5 0

Answer:

The value of the expression = 200

Step-by-step explanation:

The given expression is $\frac{6.6 * 10^{-2}}{3.3*10^{-4}}$

Using the low of exponent $x^{a} /x^{b} = x^{a-b}$

So, the expression =

$\frac{6.6 * 10^{-2}}{3.3*10^{-4}} = \frac{6.6}{3.3} * 10^{-2 -(-4)} = 2 * 10^{2} = 2*100=200$

<u>So, The value of the expression = 200</u>

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Plss help me solve these 2 !!!!!!!!!!! for a brainlist ;))

lisabon 2012 [21]

Answer:

1. d

2. a

Step-by-step explanation:

Thats how it goes!

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3 0

2 years ago

A right rectangular prism is shown. The two dimensional net is also shown. Find the surface area of this prism.

Natasha_Volkova [10]

Hey!

------------------------------------------------

Surface Area Formula: 2LW * 2LH * 2WH

------------------------------------------------

2LW:

5 x 1 = 5

5 x 2 = 10

------------------------------------------------

2LH:

4 x 1 = 4

4 x 2 = 8

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2WH:

5 x 4 = 20

20 x 2 = 40

------------------------------------------------

Surface Area:

40 + 8 + 10= 58

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Answer:

D) 58 cm2

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Hope This Helped! Good Luck!

5 0

2 years ago

Find the surface area of the square pyramid 8mm 6mm

bija089 [108]

Answer:

136 mm²

Step-by-step explanation:

$A=a^{2} +2a\sqrt{\frac{a^{2} }{4} } +h^{2}$

$A=6^{2} +2(6)\sqrt{\frac{6^{2} }{4} } +8^{2}$

$A=36 +12\sqrt{\frac{36 }{4} } +64$

$A=36 +12\sqrt{9 } +64$

$A=36 +12(3)+64$

$A=36 +36+64$

A = 136

5 0

2 years ago

A community college has a math placement exam that has a mean of 65 and a standard deviation of 8.2. If a student takes the exam

Marat540 [252]

Answer:

The score that cuts off the bottom 2.5% is 48.93.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 65, \sigma = 8.2$