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3 years ago

What is the value of the expression, written in standard form?

Mathematics

2 answers:

Pavel [41]3 years ago

6 0

Answer:

I agree with the person above me the that correct answer is 200

Step-by-step explanation:

I also just did the question

I hope this helps you!!

Studentka2010 [4]3 years ago

5 0

Answer:

The value of the expression = 200

Step-by-step explanation:

The given expression is $\frac{6.6 * 10^{-2}}{3.3*10^{-4}}$

Using the low of exponent $x^{a} /x^{b} = x^{a-b}$

So, the expression =

$\frac{6.6 * 10^{-2}}{3.3*10^{-4}} = \frac{6.6}{3.3} * 10^{-2 -(-4)} = 2 * 10^{2} = 2*100=200$

<u>So, The value of the expression = 200</u>

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HELP pls if you know this

KengaRu [80]

Answer:

Step-by-step explanation:

6 0

3 years ago

Test the null hypothesis Upper H 0 : (mu 1 minus mu 2 )equals 0H0: μ1−μ2=0 versus the alternative hypothesis Upper H Subscript a

Law Incorporation [45]

Answer:

The test statistic t is t=2.9037.

The null hypothesis is rejected.

For a significance level of 0.05, there is enough evidence to support the alternative hypothesis.

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>The sample 1, of size n1=25 has a mean of 1.15 and a standard deviation of 0.31. </em>

<em>The sample 2, of size n2=25 has a mean of 0.95 and a standard deviation of 0.15. </em>

This is a hypothesis test for the difference between populations means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is α=0.05.

The difference between sample means is Md=0.2.

$M_d=M_1-M_2=1.15-0.95=0.2$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{0.31^2+0.15^2}{25}}\\\\\\s_{M_d}=\sqrt{\dfrac{0.119}{25}}=\sqrt{0.005}=0.069$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.2-0}{0.069}=\dfrac{0.2}{0.069}=2.9037$

The degrees of freedom for this test are:

$df=n_1+n_2-1=25+25-2=48$

This test is a two-tailed test, with 48 degrees of freedom and t=2.9037, so the P-value for this test is calculated as (using a t-table):

$P-value=2\cdot P(t>2.9037)=0.0056$

As the P-value (0.0056) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

8 0

3 years ago

Find the derivative of y=8ln(sin t+9)

ira [324]

$\bf y=8ln[sin(t+9)]\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=8\cdot \cfrac{cos(t+9)\cdot 1}{sin(t+9)}\implies \cfrac{dy}{dx}=8cot(t+9)$

6 0

3 years ago

HELP PLEASE!! Which of the following best describes the graph below? A. it us a one-to-one function B. it us a function but it i

masha68 [24]

The correct statement regarding the function $y = \sqrt{x + 2}$ is given by:

A. it us a one-to-one function.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on the internet, the function used is $y = \sqrt{x + 2}$ .

<h3>Is it a function?</h3>

For $y = \sqrt{x + 2}$ , each value of x is associated with only one value of y, that is, the graph has <u>no vertically aligned points</u>, hence it is a function.

<h3>Is the function one-to-one?</h3>

Each value of y is also associated with only one value of x, that is, the graph has <u>no horizontally aligned points</u>, hence it is a one-to-one function, and the correct statement is given by:

A. it us a one-to-one function.

More can be learned about functions at brainly.com/question/24808124

#SPJ1

8 0

2 years ago

What is the maximum value of the picture below?

Cloud [144]

Answer:

y = 4

Step-by-step explanation:

The maximum value occurs at the vertex

vertex = (2, 4 )

when x = 2 the maximum value is y = 4

4 0

3 years ago