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ZanzabumX [31]
3 years ago
14

20pts Divide algebraic fraction pls 12a2/18b2÷4a/3b

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

3a/6b

Step-by-step explanation:

12a^2/4a

= 12/4 * a^2/a

= 3a

18b^2/3b

= 18/3 * b^2/b

= 6b

Hence, the answer is 3a/6b.

Hope this helped!

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PLEASE HELP!!!!! 2.) What is the perimeter of a polygon with vertices at (-3, 1), (5, 1), (-3, 4), (5, 4)? 30 points if you can
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Solve the proportional<br> equation below:<br> x/4 = x-6/3
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<h2><u>PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>

Apply the means-extremes property of proportions: this allows you to cross multiply:

                \boxed{\mathsf{\dfrac{x}{4} = \dfrac{x - 6}{3}}}

\mathsf{\dfrac{x}{4} \searrow \dfrac{x - 6}{3}}      ‏‏‎      ‏‏‎‎      \mathsf{\dfrac{x}{4} \nearrow \dfrac{x-6}{3}}‏‏‎‎

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Y=-1/3x^2-4x-5 in vertex form
grigory [225]

Answer:

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

Step-by-step explanation:

Given function:

Y=-\frac{1}{3}x^2-4x-5

We need to find the vertex form which is.,

y=a(x-h)^2+k

where (h,k) represents the co-ordinates of vertex.

We apply completing square method to do so.

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First of all we make sure that the leading co-efficient is =1.

In order to make the leading co-efficient is =1, we multiply each term with -3.

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Isolating x^2 and x terms on one side.

Subtracting both sides by 15.

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square of half of the co-efficient of x term = (\frac{1}{2}\times 12)^2=(6)^2=36

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Dividing both sides by -3.

\frac{-3Y}{-3}=\frac{(x+6)^2}{-3}-\frac{21}{-3}

Y=-\frac{1}{3}(x+6)^2+7   [Vertex form]

8 0
3 years ago
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