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soldi70 [24.7K]
3 years ago
5

What’s the answer for this d=24ft

Mathematics
2 answers:
Sunny_sXe [5.5K]3 years ago
8 0

Answer:

12ft :)

Step-by-step explanation:

Radius= 24 feet/ 2= 12 feet

I am Lyosha [343]3 years ago
7 0

Answer:

well, there is not any context, so im afraid i can't help you. sorry, dude.

Step-by-step explanation:

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All the while the dog sat in the snow, its wolf-brush of a tail curled around warmly over its forefeet, its wolf-ears are forwar
nalin [4]

Answer:21

Step-by-step explanation:

4 0
3 years ago
Ahmed writes that he needs 8 lbs of flour. To make an exact measurement with no flour left over. Which measuring cup should he u
kolezko [41]
4/5 because it goes evenly into 8
4 0
3 years ago
Express the area of the triangle shown below in terms of b and θ only.
Paul [167]
Given a right triangle with base, b and height, h with the angle opposide side h as θ.

The area of a triangle is given by
A= \frac{1}{2} bh

But,
\tan\theta= \frac{h}{b}  \\  \\ \Rightarrow h=b\tan\theta

Therefore, the area of the triangle in terms of <span>b and θ only is given by
A= \frac{1}{2} b(b\tan\theta)= \frac{1}{2} b^2\tan\theta</span>
8 0
3 years ago
Suppose that the functions q and r are defined as follows.
satela [25.4K]

Answer:

(r o g)(2) = 4

(q o r)(2) = 14

Step-by-step explanation:

Given

g(x) = x^2 + 5

r(x) = \sqrt{x + 7}

Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

g(x) = x^2 + 5

g(2) = 2^2 + 5

g(2) = 4 + 5

g(2) = 9

Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

Next, we calculate g(r(2))

Substitute 3 for r(2)in g(r(2))

g(r(2)) = g(3)

g(x) = x^2 + 5

g(3) = 3^2 + 5

g(3) = 9 + 5

g(3) = 14

Hence:

(q o r)(2) = 14

8 0
2 years ago
Number 2 to 4 I don’t understand it.
Natalka [10]
All estimating problems make the assumption you are familar with your math facts, addition and multiplication. Since students normally memorize multiplication facts for single-digit numbers, any problem that can be simplified to single-digit numbers is easily worked.

2. You are asked to estimate 47.99 times 0.6. The problem statement suggests you do this by multiplying 50 times 0.6. That product is the same as 5 × 6, which is a math fact you have memorized. You know this because
.. 50 × 0.6 = (5 × 10) × (6 × 1/10)
.. = (5 × 6) × (10 ×1/10) . . . . . . . . . . . by the associative property of multiplication
.. = 30 × 1
.. = 30


3. You have not provided any clue as to the procedure reviewed in the lesson. Using a calculator,
.. 47.99 × 0.6 = 28.79 . . . . . . rounded to cents


4. You have to decide if knowing the price is near $30 is sufficient information, or whether you need to know it is precisely $28.79. In my opinion, knowing it is near $30 is good enough, unless I'm having to count pennies for any of several possible reasons.
5 0
3 years ago
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