I think this is the answer :)
65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
Learn more about Sequences on:
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Answer:
See below.
Step-by-step explanation:
If the exponent is a/b then a is the power and b is the value of the radical.
Example: x^2/3 = ∛x². 2 is the power and 3 is the radical.
Answers:
1) 7^2/3 = ∛7²
5) √3 = 3^1/2
9) (∛27)⁴ = 27^4/3 = 3^4 = 81.
Answer:2
Step-by-step explanation:
15/3 = 5
15/2 = 7.5
+1
= 13
15 - 13 = 2
Answer:
w = - 15
Step-by-step explanation:
Assuming you mean
= - 4 ( multiply both sides by 3 to clear the fraction )
w + 3 = - 12 ( subtract 3 from both sides )
w = - 15
