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algol13
2 years ago
14

The formula=A+2lh+2wh gives surface area a. Of a rectangler solid with length, width, and height, L,W, and H, respectively solve

the formula for L
Mathematics
1 answer:
iogann1982 [59]2 years ago
6 0

Answer:

l= \frac{A}{2h} -w

Step-by-step explanation:

The question is not correct (particularly the expression for the area)

 A=2lh+2wh

Now we are expected to solve for l, that is we are going to make l subject of the formula, we have

let us take the second term on the RHS to the LHS

A-2wh= 2lh

we can now divide both sides by 2h we have

\frac{A-2wh}{2h} = l\\\\l=\frac{A}{2h} -\frac{2wh}{2h} \\\\l= \frac{A}{2h} -w

hence the expression for the length is  l= \frac{A}{2h} -w

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Olenka [21]

Answer:

4x2-9

Step-by-step explanation:

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3 years ago
What is an equation of the line that passes through the point (3, -8) and has slope -2?
BabaBlast [244]

Answer:

Step-by-step explanation:

slope of -2 means the slope is -2/1

from (3, - 8) you can find the y intercept by going backwords until x = 0

(2,-6)

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2 years ago
Please explain how you got the answer!
ValentinkaMS [17]
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We wouldn't want the same piece of information, would we?

That's why we want a new piece of information:
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6 0
2 years ago
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SpyIntel [72]

Answer:

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Step-by-step explanation:

6 0
3 years ago
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Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
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