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Nadusha1986 [10]
3 years ago
9

Please help me with this. I'm stuck

Mathematics
2 answers:
Anon25 [30]3 years ago
8 0

Answer:

Step-by-step explanation:

7 choose 2    or    

=7! / (7-2)!

=7*6*5*4*3*2*1  /  5*4*3*2*1

=7*6

=42

MatroZZZ [7]3 years ago
5 0

Answer:

It is 42!

Step-by-step explanation:

Your welcome! :)

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babymother [125]
I believe your answer is A.
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I don't know what the first step is
oksano4ka [1.4K]
Add all of the ounces in the basket.
6 2/3+3 1/2+ 5
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Please help with my algebra homework and explain if you can : v= pi/3 rsquared h
Tanzania [10]

To isolate the variable means to have it by itself on one side of the equation, where the variable equals an expression.

To isolate h, we will need to remove the variables and other terms "connected" to the h variable:

V = \dfrac{\pi}{3}r^2h

\dfrac{V}{r^2} = \dfrac{\pi}{3}h

\boxed{\dfrac{3V}{r^2\pi} = h}

By dividing terms "connected" to our h variable, we have isolated it one side of the equation.

6 0
3 years ago
2x2 + 14x- 4 = - x2 + 3x
Firlakuza [10]

first, lets solve by factoring:

Let's solve your equation step-by-step.

2x2+14x−4=−x2+3x

Step 1: Subtract -x^2+3x from both sides.

2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)

3x2+11x−4=0

Step 2: Factor left side of equation.

(3x−1)(x+4)=0

Step 3: Set factors equal to 0.

3x−1=0 or x+4=0

x=

1

3

or x=−4

we can also solve using the quadratic formula:

2x2+14x−4=−x2+3x

Step 1: Subtract -x^2+3x from both sides.

2x2+14x−4−(−x2+3x)=−x2+3x−(−x2+3x)

3x2+11x−4=0

Step 2: Use quadratic formula with a=3, b=11, c=-4.

x=

−b±√b2−4ac

2a

x=

−(11)±√(11)2−4(3)(−4)

2(3)

x=

−11±√169

6

x=

1

3

or x=−4

lastly, we can complete the square.

2x2+14x−4=−x2+3x

Step 1: Add x^2 to both sides.

2x2+14x−4+x2=−x2+3x+x2

3x2+14x−4=3x

Step 2: Subtract 3x from both sides.

3x2+14x−4−3x=3x−3x

3x2+11x−4=0

Step 3: Add 4 to both sides.

3x2+11x−4+4=0+4

3x2+11x=4

Step 4: Since the coefficient of 3x^2 is 3, divide both sides by 3.

3x2+11x

3

=

4

3

x2+

11

3

x=

4

3

Step 5: The coefficient of 11/3x is 11/3. Let b=11/3.

Then we need to add (b/2)^2=121/36 to both sides to complete the square.

Add 121/36 to both sides.

x2+

11

3

x+

121

36

=

4

3

+

121

36

x2+

11

3

x+

121

36

=

169

36

Step 6: Factor left side.

(x+

11

6

)2=

169

36

Step 7: Take square root.

x+

11

6

=±√

169

36

Step 8: Add (-11)/6 to both sides.

x+

11

6

+

−11

6

=

−11

6

±√

169

36

x=

−11

6

±√

169

36

x=

1

3

or x=−4

Answer:

x=

1

3

or x=−4

5 0
3 years ago
What is (1+2x3) squared
kobusy [5.1K]

Answer:

\large\boxed{(1+2x^3)^2=4x^6+4x^3+1}

Step-by-step explanation:

(1+2x^3)^2\\\\\bold{METHOD\ 1:}\\\\(1+2x^3)^2=(1+2x^3)(1+2x^3)\qquad\text{use FOIL}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(1)(1)+(1)(2x^3)+(2x^3)(1)+(2x^3)(2x^3)\\\\=1+2x^3+2x^3+4x^6\qquad\text{combine like terms}\\\\=1+4x^3+4x^6

\bold{METHOD\ 2:}\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\(1+2x^3)^2=1^2+2(1)(2x^3)+(2x^3)^2\\\\=1+4x^3+2^2(x^3)^2\\\\=1+4x^3+4x^6

3 0
2 years ago
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