Question

I WILL GIVE BRAINLIEST!!!

Answer 1

Let's see what to do buddy....

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Step (1)

Express taxi charges 2.50 $ per mile.

So if each mile equals x the taxi charges 2.50 x.

There's the starting fare too.

So ;

Express taxi charges by the following function :

$f(x) = 2.5x + 10$

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Step (2)

Speedy taxi charges 3 $ per mile.

So if each mile equals x the taxi charges 3x .

There's no starting fare.

So ;

Speedy taxi charges by the following function :

$g(x) = 3x$

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Step (3)

To find that after how many miles is the cost of both taxi services the same , we must equal their functions.

Then solve for x .

So we have :

$f(x) = g(x)$

$2.5x + 10 = 3x$

Subtract the sides of the equation minus 2.5x :

$10 = 0.5x$

$10 = \frac{1}{2}x$

Multiply the sides of the equation by 2 :

$x = 20$

So after 20 miles both taxi services have the same cost.

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And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

Answer 2

Answer:

Answer is after 20 miles

Step-by-step explanation:

10 +2.5x = 3x

10 = 3x-2.5x

10=0.5x

10/.5=x

x=20

At 20 miles they both have a cost of 60