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navik [9.2K]
3 years ago
11

Consider the graph. Which inequality best represents the graph?

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

y >= x/2 - 1

Step-by-step explanation:

the slope (rise/run) is 1/2 and the y-intercept is -1 so in point-slope form

y = x/2 - 1 but everything above the line (unshaded part) is valid so y is equal to or greater than.

You might be interested in
A food truck owner randomly samples 100 customers on two separate days to see what food items they bought. The data shows the re
svetlana [45]
Percentage of people who buy Burgers = 35+45/2 = 80/2 = 40

Total Number of people = 900

So, 900 * 40%

= 900 * 0.40

= 360

In short, Your Answer would be: 360 burgers

Hope this helps!
6 0
3 years ago
Read 2 more answers
An interior automotive supplier places several electrical wires in a harness.Apull test measures the force required to pull spli
oksano4ka [1.4K]

Answer:

a) For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assumin Normal distribution

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical dsitribution

The result is on the figure attached.

b) For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

Step-by-step explanation:

For this case we have the following data:

28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4

The quantile-quantile or q-q plot is a graphical procedure in order to check the validity of a distributional assumption for a data set. We just need to calculate "the theoretically expected value for each data point based on the distribution in question".

If the values are asusted to the assumed distribution, we will see that "the points on the q-q plot will fall approximately on a straight line"

For this case our distribution assumed is normal.

Part a

For this case we can use the following R code to construct the qq plot

> data<-c(28.8, 24.4, 30.1, 25.6, 26.4, 23.9, 22.1, 22.5, 27.6, 28.1, 20.8, 27.7, 24.4, 25.1, 24.6, 26.3, 28.2, 22.2, 26.3, 24.4)

# The above line is in order to store the data in a vector

> qqnorm(data, pch = 1, frame = FALSE)

# The line above is in order to calculate the quantiles from the data assuming Normal distribution (0,1)

> qqline(data, col = "steelblue", lwd = 2)

# The line above is in order to put a line for the theoretical distribution

The result is on the figure attached.

Part b

For this case as we can see on the figure attached the calculated quantiles are not far from the theorical quantiles given byt the straaigth blue line so then we can conclude that the distribution seems to be normal.

4 0
3 years ago
Solve -1.2x+2.5=0.8x+6.5<br>x=2<br>O<br>x=-4 0​
Bond [772]

Answer:

x = - 2

Step-by-step explanation:

Given

- 1.2x + 2.5 = 0.8x + 6.5 ( subtract 0.8x from both sides )

- 2x + 2.5 = 6.5 ( subtract 2.5 from both sides )

- 2x = 4 ( divide both sides by - 2 )

x = - 2

4 0
3 years ago
Dr. Gilmore gives Lily 17 pills to take. He told her to take one every six hours. In how many days will she take the last pill?
MArishka [77]
5 days because there are 24 hours in a day so every six hours you can take 4 a day
3 0
3 years ago
Please answer this simple question!!!
vladimir1956 [14]
Just substitute the value of x from equation 2 in equation 1, 
6y = x - 12
6y = 22 - 12
y= 10/6
y = 5/3

In short, Your Answer would be Option Option B) (22, 5/3)

Hope this helps!
6 0
3 years ago
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