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Marina CMI [18]
3 years ago
5

I have no clue on how to solve this

Mathematics
2 answers:
VMariaS [17]3 years ago
8 0

1, 12 2/3 is your answer


kow [346]3 years ago
8 0

1,12 so your answer
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**URGENT<br>033.012 divided by <br>6.3​
anastassius [24]

Answer:

5.24

Step-by-step explanation:

33.012/6.3=5.24

3 0
3 years ago
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!<br> Show your work
cestrela7 [59]
Well start with reflecting abc over the y axis
7 0
3 years ago
It is known that 1.4&lt; square root of 2 &lt;1.5. Find all possible values of the expression 2-square root of 2. How do I find
horsena [70]

Answer:

0.5<2-√2<0.6

Step-by-step explanation:

The original inequality states that 1.4<√2<1.5

For the second inequality, you can think of 2-√2 as 2+(-√2).

Because of the "properties of inequalities", we know that when a positive inequality is being turned into a negative, the numbers need to swap and become negative. So, the original inequality becomes -1.5<-√2<-1.4. (Notice how the √2 becomes negative, too). This makes sense because -1.5 is less than -1.4.

Using our new inequality, we can solve the problem. Instead of 2+(-√2), we are going to switch "-√2" with both possibilities of -1.5 and -1.6. For -1.5, we would get 2+(-1.5), or 0.5. For -1.4, we would get 2+(-1.4), or 0.6.

Now, we insert the new numbers into the equation _<2-√2<_. The 0.5 would take the original equation's "1.4" place, and 0.6 would take 1.5's. In the end, you'd get 0.5<2-√2<0.6. All possible values of 2-√2 would be between 0.5 and 0.6.

Hope this helped!

4 0
3 years ago
Each small square on the grid is 1 ft squared.
Shalnov [3]
Approximately 50ft because 5 put into the shape would be around 48 and it would be the best estimate of 50
3 0
3 years ago
The components of vector A are (10.5, 10.2). Waht is the magnitude of the vector?
Nataly_w [17]

Answer:

||\overrightarrow{v}||\approx14.64

Step-by-step explanation:

The magnitude of a vector \displaystyle \overrightarrow{v}=\langle x,y\rangle is ||\overrightarrow{v}||=\sqrt{x^2+y^2}, which essentially describes the length of the vector itself between the initial and terminal points:

||\overrightarrow{v}||=\sqrt{x^2+y^2}\\\\||\overrightarrow{v}||=\sqrt{(10.5)^2+(10.2)^2}\\\\||\overrightarrow{v}||=\sqrt{110.25+104.04}\\\\||\overrightarrow{v}||=\sqrt{214.29}\\\\||\overrightarrow{v}||\approx14.64

6 0
2 years ago
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