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earnstyle [38]
3 years ago
12

The area of a racquetball court is 800 square feet.The length of a standard court is twice as its width. What are the dimensions

of a standard racquetball court?
Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

Given - area of a racquet ball court is 800 square feet.

length is the twice of the width

find out thedimensions of the racquet ball court.

To proof -

Formula

area of a rectangle = length×breadth

 as given inthe question the length of court is twice of its width .

let assume width be w

than  length become 2w

put in the formula

w×2w = 800 ft²

2w² = 800 ft²

w = \sqrt{400} ft

w = 20 ft

Than the length become 40 ft.

Hence proved


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adding the 2 equations side by side we have:

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expanding the binomial, and collecting same terms we have:

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dividing by -5:

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dividing by 3:

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Answer: \displaystyle{f(x)= \frac{1}{5}x^2+ \frac{2}{3}x-\frac{5}{3}

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Algebra 2 Questions:
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Answer:

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On substituting the value of y =6 in the equation 7y = 8x -14 to solve for x.

7(6)= 8x - 14

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Add 14 to both sides in equation [1];

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56 = 8x              

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Division Property of equality states that you divide the same number to both sides of an equation.

Divide by 8 to both sides of an equation [2];

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Simplify:

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A two Column proof:

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1. 7y = 8x -14                                   Given

    y= 6

2. 7(6) = 8x -14                                Substitution property

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4.   56 =8x                                       Simplify

5.    x =7                                           Division Property of equality

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Answer:

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Then multiply

16 -8 +8 -2

Then add and subtract

14

4 0
3 years ago
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