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earnstyle [38]
4 years ago
12

The area of a racquetball court is 800 square feet.The length of a standard court is twice as its width. What are the dimensions

of a standard racquetball court?
Mathematics
1 answer:
zubka84 [21]4 years ago
3 0

Given - area of a racquet ball court is 800 square feet.

length is the twice of the width

find out thedimensions of the racquet ball court.

To proof -

Formula

area of a rectangle = length×breadth

 as given inthe question the length of court is twice of its width .

let assume width be w

than  length become 2w

put in the formula

w×2w = 800 ft²

2w² = 800 ft²

w = \sqrt{400} ft

w = 20 ft

Than the length become 40 ft.

Hence proved


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Answer:

18.84 feet.  let me know if you have ay other questions.

Step-by-step explanation:

The way to find the formula for circumference is kinda complicated so it is best to ust memorize the formula, which is 2πr.  or 2 times pi times the radius.  

Your problem gives you the formula, but instead of 2 and r in it you have d, which is the diameter.

The diameter of the circle is 2 times the radius, so that's why it is replaced.

the radius is the distance from the center fo the circle to one edge, and the diameter is the distance through the circle passing through its center.  so it's the center to one end plus the center to another end.  or r+r which is also 2r.

So d = 2r, so in this problem d =6 feet.

So now the formula πd = 3.14*6 feet = 18.84 feet

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