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marishachu [46]
3 years ago
12

Equation in slope intercept form of (-3,4) and (1,4)

Mathematics
2 answers:
postnew [5]3 years ago
7 0
The equation is y=4. hoped this helped
crimeas [40]3 years ago
4 0

The two points have the same y coordinate, which means that the line is horizontal, which means that the slope is 0.

So, the equation is y=4

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Each notebook contains 60 sheets of paper. Andre has 5 notebooks. If the equation is y=5x60 then what does y stand for?
AveGali [126]

Answer:

y = the total sheets in all 5 notebooks

Step-by-step explanation:

5 = notebooks

60 = sheets

y = the total

3 0
3 years ago
Read 2 more answers
LA plane is trying to travel 250 miles at a bearing of 20° E of S, however, it ends 230 miles away from the
Semmy [17]

Answer:

The wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} East of North  with respect to the destination point.

Step-by-step explanation:

Let origin, O, br the starting point and point D be the destination at 250 miles at a bearing of 20° E of S, but due to wind let D' be the actual position of the plane at 230 miles away from the  starting point in the direction of 35° E of South as shown in the figure.

So, we have |OD|=250 miles and |OD'|=230 miles.

Vector \overrightarrow{DD'} is the displacement vector of the plane pushed by the wind.

From figure, the magnitude of the required displacement vector is

|DD'|=\sqrt{|AB|^2+|PQ|^2}\;\cdots(i)

and the direction is \alpha east of north as shown in the figure,

\tan \alpha=\frac{|PQ|}{|AB|}\;\cdots(ii)

From the figure,

|AB|=|OA-OB|

\Rightarrow |AB|=|OD\cos 20 ^{\circ}-OD'\cos 35 ^{\circ}|

\Rightarrow |AB|=|250\cos 20 ^{\circ}-230\cos 35 ^{\circ}|

\Rightarrow |AB|=45.52 miles

Again, |PQ|=|OP-OQ|

\Rightarrow |PQ|=|OD\sin 20 ^{\circ}-OD'\sin 35 ^{\circ}|

\Rightarrow |PQ|=|250\sin 20 ^{\circ}-230\sin 35 ^{\circ}|

\Rightarrow |PQ|=46.42 miles

Now, from equations (i) and (ii), we have

|DD'|=\sqrt{|45.52|^2+|46.42|^2}=65.01 miles, and

\tan \alpha=\frac{|46.42|}{|45.52|}

\alpha=\tan^{-1}\left(\frac{|46.42|}{|45.52|}\right)=45.56 ^{\circ}

Hence, the wind pushed the plane 65.01 miles in the direction of 45.56 ^{\circ} E astof North  with respect to the destination point.

5 0
3 years ago
Help please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
SpyIntel [72]
Hang in there just a sec
4 0
3 years ago
2 Points
alexdok [17]

Answer:

Rx)=1/3x^2

Step-by-step explanation:

A horizontal stretch is simply making the parabola of the parent function wider, it's kind of like changing the slope of a line to make it less steep.

In the graph, the red line is the parent function and the blue line is the horizontally stretched function.  See how the blue line appears to be stretched (horizontally).

4 0
3 years ago
What is 97,000 in scientific notation?
lianna [129]

Answer:

9.7 * 10 to power of 4

Step-by-step explanation:

7 0
3 years ago
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